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2 years ago

A pond located in a town was drained to make room for the new factory. Which change is likely to occur?

Biology

1 answer:

lubasha [3.4K]2 years ago

7 0

Answer:

A. Shorebirds will not be able to nest in the area.

Explanation:

Habitat is the environment where animals and humans lives and are favorable to their living condition.

If a pond in town was drained to make room for the new factory it will destroy the habitat of its native animal or birds. It means shorebirds will not be able to nest in the area as the construction of new factory will change the condition of the habiat causing more pollution and no facility of water( due pond drainage).

Hence, due to Habitat destruction through which natural habitat becomes unacceptable of supporting its native species, Shorebirds will not be able to nest in the area.

The correct option is A.

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The rate at which the concentration of a drug in the bloodstream decreases is proportional to the concentration at any time t. I

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Answer:

$C(t) = C_oe^{-kt}$

Explanation:

From the given information:

At any given time (t), let c(t) represent the concentration of the drug present in bloodstream.

Deriving the equation:

$\dfrac{dC}{dt}$ decrease proportionally to Concentration C

i.e

$\dfrac{dc}{dt} \alpha - C$

$\dfrac{dc}{dt} = -k C$

$\dfrac{dc}{c} = -k dt$

$\int \dfrac{dc}{c} = -k \int dt$

㏑(C) = -kt + λ

where,

λ is the integration constant.

Integrating at t = 0, concentration of blood = Co g/mL

C(0) = Co

㏑(C₀) = 0 + λ

λ = ㏑(C₀)

From ㏑(C) = -kt + λ

㏑(C) = -kt + ㏑C₀

㏑(C) - ㏑C₀ = -kt

$\dfrac{C}{C_o} = e^{-kt}$

$C(t) = C_oe^{-kt}$

∴

The concentration of drug in blood at any time t is:

$C(t) = C_oe^{-kt}$

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