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Yakvenalex [24]

3 years ago

12

Given the following exponential function, identify whether the change represents growth or decay , and determine the percentage

rate of increase or decrease y =550(1.075)x

1 answer:

jenyasd209 [6]3 years ago

8 0

Answer:

It is growth and the percentage rate of increase is 7.5%

Step-by-step explanation:

The exponential equation is as follows;

y = 550(1.075)^x

Now, I can identify that the exponential equation is that of growth.

This is because what is in the bracket i.e can be represented as 1+ 0.075

The 0.075 represents the margin of increase as we move on from one value to another

The percentage rate can be gotten by expressing 0.075 as a percentage

That would be expressing is as a fraction

This is just 7.5/100 which means what we have is 7.5%

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Sole thus problem for 10 points 2x^2-4+10=0

Vlada [557]

Answer:

x∉R

Step-by-step explanation:

6 0

2 years ago

Find b<br> Round to the nearest tenth:<br> c<br> 8 cm<br> 820<br> 550<br> b<br> b = [? ]cm

gogolik [260]

Answer:

5.50961, or 5.5

Hope that this helps!

8 0

2 years ago

Read 2 more answers

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

Please help me with this problem..

charle [14.2K]

Answer:

y = 6

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 3 when x = 9, then

k = $\frac{y}{x}$ = $\frac{3}{9}$ = $\frac{1}{3}$ , thus

y = $\frac{1}{3}$ x ← equation of variation

When x = 18, then

y = $\frac{1}{3}$ × 18 = $\frac{18}{3}$ = 6

5 0

3 years ago

Sandy has $200 in her bank account.

Mademuasel [1]

The answer it is b because that is the right answer

3 0

3 years ago