Answer:24/3
Step-by-step explanation:
Answer:
The largest integer is 29.
Step-by-step explanation:
Let the consecutive positive integers are x, x+1 and x+2.
The square of sum of squares of three consecutive positive integers is 2354 such that,
![x^2+(x+1)^2+(x+2)^2=2354\\\\x^2+x^2+2x+1+x^2+4+4x=2354\\\\3x^2+6x+5=2354\\\\3x^2+6x- 2349=0](https://tex.z-dn.net/?f=x%5E2%2B%28x%2B1%29%5E2%2B%28x%2B2%29%5E2%3D2354%5C%5C%5C%5Cx%5E2%2Bx%5E2%2B2x%2B1%2Bx%5E2%2B4%2B4x%3D2354%5C%5C%5C%5C3x%5E2%2B6x%2B5%3D2354%5C%5C%5C%5C3x%5E2%2B6x-%092349%3D0)
It is a quadratic equation whose solution is given by :
x = 27 and x = -29
First positive integer = 27
Second positive integer = 27+1 = 28
Third positive integer = 27+2 = 29
Hence, the largest integer is 29.
Answer:
HWHHSAHhhj
Step-by-step explanation:
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Answer:
f jb gfbjfmnb fjb
Step-by-step explanation:
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