Answer: 12 yearly admissions and 38 single admissions
Step-by-step explanation:
Let x be yearly membership
Let y be single admission
x+y=50 --> # of tickets sold
35.25x+6.25y=660.50 --> $ of tickets
Use elimination method to solve (multiply equation 1 by -3525 and equation 2 by 100)
-3525x-3525y=-176250
+ 3525+625y=66050
-----------------------------------
-2900y=-110200
y=38
Substitute y=38 into equation 1
x+38=50
x=12
Therefore, 12 yearly admissions and 38 single admissions were sold
Answer:
yes it CAN have more than 1
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Answer:
sorry if image isn't clear, tried many shots
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Answer:
wat is the actual question for this??
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