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True [87]
3 years ago
9

Bethany, Lauren, Amanda, and David all meet at a family reunion. They are comparing their ages. They have found that Lauren is 1

3 years older than Bethany and David is 11 years older than Amanda. They also found that the product of Bethany's and Lauren's ages is equal to twice Amanda's age. Also, if they subtract 20 years from both Bethany's and Lauren's age, the product is equal to David's age.
If x represents Bethany's age and y represents Amanda's age, then which of the following systems of equations can be used to determine the ages of all four family members based on their findings?

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0
Lauren =l
David=d
Bethany's =x
Amanda =y
l=x+13
d=y+11
lx=2y
<span>(x+13)x=2y
</span>2y=x^2+13x
y= \frac{1}{2}(x^2+13x)
or
y= \frac{x^2}{2}+ \frac{13}{2}x
(x-20)(l-20)=d
<span>(x-20)(x+13-20)=y+11 </span><span>
</span>y+11=(x-20)(x-7)
y+11=x^2-27x+140
y=x^2-27x+129
so I believe its b
Hope this helps :)
Natali5045456 [20]3 years ago
3 0

its D for plato users

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Step-by-step explanation:

Let the length of the board is = l feet

Marty saws off \frac{1}{5} of a wooden board.

Length of the board left = l - (\frac{1}{5})l

                                        = (\frac{4}{5})l feet

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Board left = (\frac{4}{5})l-[(\frac{4}{5})l\times (\frac{3}{4})]

                = \frac{4}{5}l-\frac{3}{5}l

                = \frac{1}{5}l feet

He finally saws off \frac{1}{3}rd of the remaining board.

Board left = \frac{1}{5}l-[\frac{1}{5}\times \frac{1}{3}]l

                = (\frac{1}{5}-\frac{1}{15})l

                = \frac{2}{15}l feet

Fraction of the original board left = \frac{\frac{2}{15}l}{l}

                                                       = \frac{2}{15}

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Answer: =10x+8y−12


Step-by-step explanation:

Let's simplify step-by-step.

−6x−12+8y+16x

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