X = -6y - 12
4x + 5y =-39
4x + 5y = -39
-4(-6y - 12) + 5y = -39
-4(-6y) + 4(12) + 5y = -39
24y + 48 + 5y = -39
29y + 48 = -39
29y = -87
y = -3
x = -6y - 12
x = -6(-3) - 12
x = 28 - 12
x = 6
(x, y) = (6, -3)
Answer:
Part 1) The domain of the quadratic function is the interval (-∞,∞)
Part 2) The range is the interval (-∞,1]
Step-by-step explanation:
we have

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)
step 1
Find the domain
The domain of a function is the set of all possible values of x
The domain of the quadratic function is the interval
(-∞,∞)
All real numbers
step 2
Find the range
The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.
we have a vertical parabola open downward
The vertex is a maximum
Let
(h,k) the vertex of the parabola
so
The range is the interval
(-∞,k]
Find the vertex

Factor -1 the leading coefficient

Complete the square


Rewrite as perfect squares

The vertex is the point (7,1)
therefore
The range is the interval
(-∞,1]
2/3(2/8 + 4/8) = 2/3(1/4 + 1/2)
2/3(3/4) = 1/2
Answer:
agree
Step-by-step explanation:
because they have the same slope of 3. so they are parallel with different y intercepts
Answer:
D
Step-by-step explanation:
y equals 1. x equals 15. 15 over 15 is 1.