Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>
Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get
Hence amount owed at the end of 1 year is 3640
Cross multiply to get 8k+24=56 then solve for k so subtract 24 from each side to get 8k=32 so k=4
X = additional mile
0.85x + 1.65 = 20
to solve it:
subtract 1.65 from both sides. afterwards, divide both sides by 0.85 to find x!
Answer:
84 cases
Step-by-step explanation:
Given that:
Number of trucks: 28
Paper cases each truck can load = 3
Total cases of white paper = 283
So the cases delivered will be = 28 *3 = 84 cases will be delivered today
i hope it will help you!
Answer: the first option is the correct answer.
Step-by-step explanation:
Let x represent the number of necklaces that he makes in a year.
Profit = Revenue - cost
The cost of making each necklace is $5. In making necklaces in a year, the fixed cost is $5000. This means that the total cost of making x necklaces in a year is
5x + 5000
Sam sells each necklace for $10 each. This means that the total amount made from selling x necklaces is $10x.
For Sam to make profit of $1000 in a year, the number of necklaces that she must sell would be
1000 = 10x - (5x + 5000)
1000 = 10x - 5x - 5000
10x - 5x = 1000 + 5000
5x = 6000
x = 6000/5
x = 1200
