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3 years ago

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What is the approximate distance between two points with coordinates (3, 5) and (-4, -8)? Round your answer to the nearest hundr

edth

2 answers:

OverLord2011 [107]3 years ago

8 0

14.76. (If you use a^2 x b^2 = c^2

Anika [276]3 years ago

3 0

There is a problem,in order to solve this u need a cordanite bride for them to go on.

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ANSWER ASAPPP PLSSS. ILL MARK BRAINLIEST TOO

nevsk [136]

Answer:

Step-by-step explanation:

11.04 = 10(1.02)^n

1.104 = 1.02^n

ln 1.104 = ln 1.02^n

ln 1.104 = n ln 1.02

n = ln 1.104/ ln 1.02

n = 4.99630409516

4.99 can be rounded to 5.

So a reasonable domain would be 0 ≤ x < 5

PART B)

f(0) = 10(1.02)^0

f(0) = 10(1)

f(0) = 10

The y-intercept represents the height of the plant when they began the experiment.

f(1) = 10(1.02)^1

f(1) = 10(1.02)

f(1) = 10.2

(1, 10.2)

f(5) = 10(1.02)^5

f(5) = 10(1.1040808)

f(5) = 11.040808

f(1)=10(1.02)^1

f(1)=10.2

Average rate= (fn2-fn1)/(n2-n1)

=11.04-10.2/(5-1)

=0.22

the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.

3 0

3 years ago

Read 2 more answers

I need help can u help me please and thanks

son4ous [18]

Answer:

17.74

Step-by-step explanation:

The fraction is easily converted to one with a denominator of 100 (a power of 10):

$\dfrac{37}{50}=\dfrac{37\cdot 2}{50\cdot 2}=\dfrac{74}{100}=0.74$

Then the number of interest is ...

17 37/50 = 17 74/100 = 17.74

3 0

3 years ago

Find the value of y in the formula y = 5a – 3b + c, if a = 12, b = 4, and c = 8. A. 64 B. 56 C. 40 D. 80

Orlov [11]

<span>y = 5(12) - 3(4) + 8
y = 60 - 12 + 8
y= 56</span>

3 0

3 years ago

Read 2 more answers

data set A is {30, 45, 32, 50, 33, 40, 44, 32}. Data set B is {28, 43, 30, 48, 35, 42, 46, 34}. which statement best compares th

3241004551 [841]

Answer:

the mean in set B is equal to the mean in set A (option C)

Question:

The question is incomplete as the answer choices were not given.Let's consider the following question:

Data set A is {30, 45, 32, 50, 33, 40, 44, 32}. Data set B is {28, 43, 30, 48, 35, 42, 46, 34}. which statement best compares the two data sets?

a) median for set A is equal to the median for set B

b) Range for set A is greater than range for set B

c) The mean in set B is equal to the mean in set A

Step by step explanation:

We can describe a data set using four ways:

Center, spread, shape and unusual features.

Let's consider the center and spread.

Center: This is the median of the distribution.

Spread: This is the variation of the data set. If the range is wide, the spread is larger and If the range is small, the spread is smaller.

Rearranging the data set:

A = {30, 32, 32, 33, 40, 44, 45, 50}

B = {28, 30, 34, 35, 42, 43, 46, 48}

From the data:

The median for set A = (33+40)/2 = 73/2= 36.5

The median for set B = (35+42)/2 = 77/2= 38.5

Range = highest value - lowest value

The data ranges from 30 to 50 (range = 20) for A

The data ranges from 28 to 48 (range = 20) for B

Mean for set A = (30+32+32+33+40+4445+50)/8 = 306/8 = 38.25

Mean for set B = (28+30+34+35+42+43+46+48)/8= 306/8 = 38.25

In both data set the mean is equal to 38.25.

Therefore the statement that best compares the two data sets is the mean in set B is equal to the mean in set A (C)

8 0

3 years ago

Can someone help me please

iris [78.8K]

Answer:

"I can find the maximum or minimum by looking at the factored expression of a quadratic function by reading off its roots and taking the arithmetic average of them to obtain the $x$ -coordinate of the quadratic function, and then substituting that value into the function."

Step-by-step explanation:

Because of the symmetry of quadratics (which is the case here because we have two factors of degree 1, so we are dealing with a <em>polynomial</em> of degree 2, which is a fancy way of saying that something is a quadratic), the $x$ -coordinate of the extremum (a fancy way of saying maximum or minimum) is the (arithmetic) average of the two roots.

In the factored form of a quadratic function, we can immediately read the roots: 3 and 7. Another way to see that is to solve $(x-3)(x-7)=0$ , which gives $x-3=0 \vee x-7=0$ (the 'V' stands for 'or'). We can take the average of the two roots to get the $x$ -coordinate of the minimum point of the graph (which, in this case, is $x=\frac{3+7}{2} = \frac{10}{2} = 5$ ).

Having the $x$ -coordinate of the extremum, we can substitute this value into the function to obtain the maximum or minimum point of the graph, because that will give the $y$ -coordinate of the extremum.

6 0

3 years ago