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oksano4ka [1.4K]
3 years ago
15

At a certain temperature, the equilibrium constant for the chemical reaction shown is 1.60×10−3 . At equilibrium, the concentrat

ion of AB is 1.825 M, the concentration of BC is 1.625 M, and the concentration of AC is 0.130 M. Calculate the concentration of B at equilibrium. AB(aq)+BC(aq)↽−−⇀AC(aq)+2B(aq) AB ( aq ) + BC ( aq ) ↽ − − ⇀ AC ( aq ) + 2 B ( aq ) [B] =
Chemistry
1 answer:
damaskus [11]3 years ago
6 0

Answer: Thus the concentration of B at equilibrium is 0.191 M

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c

For the given chemical reaction:

AB(aq)+BC(aq)\rightarrow AC(aq)+2B(aq)

The expression for K_c is written as:

K_c=\frac{[B]^2\times [AC]}{[BC]\times [AB]}

1.60\times 10^{-3}=\frac{(B)^2\times (0.130)}{(1.625\times 1.825)}

B=0.191M

Thus the concentration of B at equilibrium is 0.191 M

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