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larisa86 [58]
3 years ago
13

Running water can transport weathered pieces of rocks downstream what will happen to these weathered pieces of rocks and sedimen

ts when the water loses energy and moves more slowly
Chemistry
1 answer:
OleMash [197]3 years ago
8 0

Answer:

those small sediments begin to precipitate, condense on the ground and finally settle.

Explanation:

Sedimentation is a natural process, which occurs spontaneously in nature and promotes the formation of sedimentary rocks.

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Standard atmospheric pressure corresponds to the normal air pressure at sea level.
jekas [21]
Im not really sure what your asking.... <span>Standard sea-level pressure, by definition, equals 760 mm (29.92 inches) of mercury, </span>14.70 pounds per square inch<span>, 1,013.25 × 10 </span>3<span> dynes per square centimetre, 1,013.25 millibars, one standard atmosphere, or 101.325 kilopascals.

</span><span>""atmospheric pressure | Britannica.com""</span>
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3 years ago
Nitrogen-fixing bacteria live in protective nodules (bumps) on the roots of some plants. These bacteria are able to convert gase
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3 0
3 years ago
Read 2 more answers
What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?
cupoosta [38]

Answer : The value of reaction quotient, Q is 0.0625.

Solution : Given,

Concentration of N_2 = 2.00 M

Concentration of H_2 = 2.00 M

Concentration of NH_3 = 1.00 M

Reaction quotient : It is defined as a concentration of a chemical species involved in the chemical reaction.

The balanced equilibrium reaction is,

N_2+3H_2\rightleftharpoons 2NH_3

The expression of reaction quotient for this reaction is,

Q=\frac{[Product]^p}{[Reactant]^r}\\Q=\frac{[NH_3]^2}{[N_2]^1[H_2]^3}

Now put all the given values in this expression, we get

Q=\frac{(1.00)^2}{(2.00)^1(2.00)^3}=0.0625

Therefore, the value of reaction quotient, Q is 0.0625.

3 0
3 years ago
What is the. color for base??????
valina [46]
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4 0
3 years ago
Rb2co3(aq)+fec2h302(aq)--&gt;
nata0808 [166]

Answer:

Rb2CO3(aq)+Fe(C2H3O2)2(aq)--> 2Rb(C2H3O2)(aq) + FeCO3(s)

Explanation:

The reaction shown in the answer is the reaction of rubidium carbonate and iron II acetate. Rubidium is far more reducing than Fe II hence it can displace Fe II from its salt as shown.

The reducing property of metals depends on the value of their individual electrode potential values. For rubidium, its standard reduction potential is -2.98 V while that of Fe II is -0.44V. Hence rubidium can displace Fe II from its salt as shown above.

4 0
3 years ago
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