Answer:
C) 30 by 10
Step-by-step explanation:
If the rail is ten meters long, and the rope is 10 meters long, they can travel 10 meters left of the rail, ten meters along the rail, ten meters right of the rail, and ten meters above the rail.
I think the answer is 700 as 700*10=7,000.
(please open my photo for reference as you read, I am a visual learner/explainer so it will make the most sense that way)
So the first thing you want to do is look at the exterior angle 130°. A straight line is 180°, and every Triangle's angular sum is 180°. How I think of it is that every straight line has a mini protractor on either side. It makes it a bit easier to understand.
180 - 130 = 50
You now know that two of the angles are 50°.
You now have two of the measurements for the triangle farthest to the left.
75° and 50°
75 + 50 = 125
180 - 125 = 55
a = 55°
Now that you have all the measurements for the first triangle, let's move onto the next one.
With two measurements for the second triangle, all you need to do is find their sum and subtract that from 180 and you will have the third measurement!
50 + 60 = 110
180 - 110 = 70
b = 70°
Finally, for the last triangle, you already have two of the measurements 60° and 85°.
85 + 60 = 145
180 - 145 = 35
c = 35°
Sorry if this explanation is a bit messy, it's hard to describe certain things without a letter or some kind of name to differentiate between them verbally.
I hope this helps! <3
Answer:
Janelle will make <u>62 baskets</u> on 14th day.
Step-by-step explanation:
Given,
Number of goals on 1st day = 10
We need to find the number of goals on 14th day.
Solution,
Since Janelle made 10 goals on 1st day and want to make 4 more basket from the day before.
So we can say that;
and ![d=4](https://tex.z-dn.net/?f=d%3D4)
And also ![n=14](https://tex.z-dn.net/?f=n%3D14)
here
= first term
d = common difference
n = number of terms
Now we apply the formula of A.P.
![T_n=a_1+(n-1)d](https://tex.z-dn.net/?f=T_n%3Da_1%2B%28n-1%29d)
now substituting the given values, we get;
![T_{14}=10+(14-1)4\\\\T_{14}=10+13\times 4\\\\T_{14}=10+52 =62](https://tex.z-dn.net/?f=T_%7B14%7D%3D10%2B%2814-1%294%5C%5C%5C%5CT_%7B14%7D%3D10%2B13%5Ctimes%204%5C%5C%5C%5CT_%7B14%7D%3D10%2B52%20%3D62)
Hence Janelle will make <u>62 basket</u> on 14th day.
The terms in the sum are given by the sequence
![\left\{\dfrac{5^{n+1}}{3^n}\right\}_{n\ge1}](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cdfrac%7B5%5E%7Bn%2B1%7D%7D%7B3%5En%7D%5Cright%5C%7D_%7Bn%5Cge1%7D)
We have
![\dfrac{5^{n+1}}{3^n}>\dfrac{5^n}{3^n}=\left(\dfrac53\right)^n>1](https://tex.z-dn.net/?f=%5Cdfrac%7B5%5E%7Bn%2B1%7D%7D%7B3%5En%7D%3E%5Cdfrac%7B5%5En%7D%7B3%5En%7D%3D%5Cleft%28%5Cdfrac53%5Cright%29%5En%3E1)
for all
, and the series
clearly diverges, so
must also diverge.