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kupik [55]
3 years ago
14

What is the value of ▲ in the equation shown? 7x9=(7x10)-(7x▲ )

Mathematics
1 answer:
ahrayia [7]3 years ago
7 0

Step-by-step explanation:

▲ =1

easy peasy........

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Please answer i need help
skad [1K]
1. 72 to 50 points
50/72 = 69%
100-69= 31% decrease

2. 14 to 40 books
14 / 40 = 35%
100-35= 65% increase

3. 10 plus 30% increase
10 * 0.3 = 13
8 0
2 years ago
Read 2 more answers
-2(2x+3)=-4(x+1) - 2
mario62 [17]

Answer:

All real numbers are solutions

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(2x+3)=−4(x+1)−2

Step 1: Simplify both sides of the equation.

−2(2x+3)=−4(x+1)−2

(−2)(2x)+(−2)(3)=(−4)(x)+(−4)(1)+−2(Distribute)

−4x+−6=−4x+−4+−2

−4x−6=(−4x)+(−4+−2)(Combine Like Terms)

−4x−6=−4x+−6

−4x−6=−4x−6

Step 2: Add 4x to both sides.

−4x−6+4x=−4x−6+4x

−6=−6

Step 3: Add 6 to both sides.

−6+6=−6+6

0=0

Answer:

All real numbers are solutions.

8 0
3 years ago
What is an equation for a sine curve with amplitude 2, and period 4pi radians ?
Nezavi [6.7K]
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude  and  n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)

The correct answer is option D. y = 2 sin (θ/2)
===========================================

<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude  and  n = 2π/period
<span>amplitude = 5  , period = 2π/n = 2π/2 = π
</span>

The correct answer is option B. Period: pi radians: Amplitude:5

============================================================
3. tan (2π/3) = tan 120° = -√3 
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3

The correct answer is C. -sqrt3

=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3

The correct answer is <span>B.-sqrt3/3</span>
8 0
3 years ago
Two hot air balloons are traveling along the same path away from a town
mariarad [96]

Answer:

A

Step-by-step explanation:

the answer is A because I got it right on my test

7 0
3 years ago
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A researcher is interested in knowing the average height of the men in a village. To the researcher, the population of interest
Anna11 [10]

Answer:

The population mean height of men in the village is 5.78 feet.

The sample mean height of men in the village is 7.8 feet.

Step-by-step explanation:

It is provided that the researcher's interest is in knowing the average height of the men in a village.

To the researcher, the population of interest is the <em><u>men</u></em><em> </em>in the village, the relevant population data are the <em><u>height of men</u></em> in the village, and the population parameter of interest is the <em><u>mean height of men</u></em>.

It is also provided that there are 590 men in the village, and the sum of their heights is 3,410.2 feet.

Compute the average height as follows:

\bar X_{H}=\frac{3410.2}{590}=5.78\ \text{feet}

Thus, the population mean height of men in the village is 5.78 feet.

It is given that the researcher measured the heights of 18 village men and calculated the average to estimate the average height of all the village men.

The sample for his estimation is <em><u>18 men</u></em>, the relevant sample data are the <em><u>heights of the 18 men</u></em>, and the sample statistic is the <em><u>sample mean height</u></em>.

It is also given that the  sum of the heights of the 18 village men is 104.4 feet.

Compute the average height of the 18 men as follows:

\bar x_{H}=\frac{104.4}{18}=7.8\ \text{feet}

Thus, the sample mean height of men in the village is 7.8 feet.

8 0
3 years ago
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