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ruslelena [56]
3 years ago
13

Mr. Rr the Rreliable Rrobot has been programmed to whistle every 18 seconds and do a jumping jack every 42 seconds, starting fro

m the moment he is turned on. (For example, he does his first jumping jack 42 seconds after he is turned on.)
Mathematics
1 answer:
posledela3 years ago
6 0
What is this question asking for as an answer? It only has the robot's situation listed, not what the question is. Could you please put the question into further detail?
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Answer:

7 6/18

Step-by-step explanation:

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Write the equation of a straight line passing through the point (1,8) and perpendicular to y=3x+2
Neko [114]
Hello there!

The first thing you must do is to find the slope of the line. To do this, find the negative reciprocal of your current equation. Since your current slope is 3, the negative reciprocal of that would be -1/3, which would be your slope.

Now that you have your slope, plug it into the slope intercept equation as well as your known points:
(1,8)  m(slope)=-1/3
8=1(-1/3)+b

Now, solve for b:
8=1(-1/3)+b
8=-1/3+b
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Now that you have the slope and the b value, you can conclude that your equation would be:
y=-1/3x+25/3
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3 years ago
Help with this plz bc I don’t want to get I trouble by my teacher
aksik [14]

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Step-by-step explanation:

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2 years ago
Identify the standard form of the equation by completing the square.
OLEGan [10]

Answer:

\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1

Step-by-step explanation:

<u>Given equation</u>:

4x^2-9y^2-8x+36y-68=0

This is an equation for a horizontal hyperbola.

<u>To complete the square for a hyperbola</u>

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

\implies 4x^2-8x-9y^2+36y=68

Factor out the coefficient of the x² term and the y² term.

\implies 4(x^2-2x)-9(y^2-4y)=68

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2

\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36

Factor the two perfect trinomials on the left side:

\implies 4(x-1)^2-9(y-2)^2=36

Divide both sides by the number of the right side so the right side equals 1:

\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}

Simplify:

\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1

Therefore, this is the standard equation for a horizontal hyperbola with:

  • center = (1, 2)
  • vertices = (-2, 2) and (4, 2)
  • co-vertices = (1, 0) and (1, 4)
  • \textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}
  • \textsf{Foci}: \quad  (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)

4 0
1 year ago
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