For the given question above, there are other details that is missing. Here is what I got from my research.
Mass of a hydrogen atom as 1.008 u,
<span>where 1 u=1.661 times 10^-27 kg.
</span>The frequency of a mass on a spring is:
<span>f = omega / 2pi = sqrt (k/meff) / 2pi </span>
<span>The meff you use is the effective mass. If two bodies with mass M and m are both free to move: </span>
<span>Meff = Mm / (M+m) </span>
<span>If M=m, then Meff = m/2 (as you were given) </span>
<span>So the answer is: </span>
<span>f = sqrt (2k/m) / 2pi </span>
Answer:
Yes
Explanation:
Yes, bluetooth devices work in a frequency range between 2.4 - 2.485GHz. Outside this frequency the devices will not communicate with each other correctly. This frequency equals a wavelength of around 1cm. Therefore, any change in the amplitude or wavelength would need to be in relation to each other in order to maintain the frequency in the required range for the bluetooth device to work accordingly. If one increases while the other remains the same it can easily change the frequency to outside the range.
The two forces should be equal therefore:
2.10 * Fa = Fa + 2 * F * cos 18
simplifying the right side:
2.10 * Fa = Fa + 1.902 * F
1.10 Fa = 1.902 F
<span>F / Fa = 0.578</span>
Visible light
the part of the electromagnetic spectrum that the human eye is able to detect