Answer:
9194.4278 seconds
Explanation:
Orbital period is given by :
T² = (4π²r³) /GM
G = Gravitational constant = 6.67 * 10^-11
M = 5.9801 * 10^24 kg
r = (3.110 * 10^6 m + 6378000 m) =3110000 + 6378000 = 9488000 m
T² = (4π² * 9488000^3) / (6.67* 10^-11 * 5.9801*10^24)
T² = 3.37197 * 10^22 / 398872670000000
T² = 84537504.161415
T = sqrt(84537504.161415)
T = 9194.4278 seconds
Explanation:
This is one of those great problems that is harder to read than to solve!
Remember the following...
Power is the amount of work done over time.
and that work is Force times distance.
and that Force is just mass times acceleration.
So... nesting all the equations together we might get something that looks like.
We know the power, the time, the acceleration (at this given time) and the mass. We can then solve for d.
Plug and chug!
No, because 25% of their energy needs is not worth it.
Answer:
4A
Explanation:
Current is charge per time. So if the second wire delivers twice as much charge in the same amount of time, it must have twice the current.
2 × 2A = 4A