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vitfil [10]
3 years ago
9

If an electric circuit has 0 A of current running through it then .

Physics
1 answer:
Mila [183]3 years ago
6 0

Answer:

voltage and zero

Explanation:

I don't know i just did the Edg question

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Describe the evolution of a pulsar over time, in particular how the rotation and pulse signal changes over time.
madam [21]

Answer:

As beams of particles and their associated energy are given off, the pulsar will lose energy slowly, which will decrease the rate of its rotation. The frequency of pulses would therefore decrease, so that fewer pulses are observed in a given time span. The strength of the pulse signal will also decrease so the pulses will become fainter. Eventually, the pulsar should rotate so slowly and have such a low emission of radiation that it would no longer be observable.

3 0
3 years ago
Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?
kifflom [539]
Based on the law of conservation of energy, we know that we can't create energy, machines can only convert one type of energy into another. So, if we want to improve a machines's ability then we need to reduce it's loss energy (part of energy which is useless). Out of all the options only Option C fits best with it.

In short, Your Answer would be Option C

Hope this helps!
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3 years ago
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4. If the Kitty Hawk Flyer has 12 HP, do some research to find out how to express this power in the SI system and report the num
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Product of my research: 1 HP = 746 watts .

12 HP = (12 x 746 W) = 8,952 W

8,952 W = 8.952 kW
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Como se dice casa en náhuatl​
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2 years ago
A piano emits frequencies the range from a low of about 28 Hz to a high of about 4200 Hz. Find the range of wavelengths in air a
Step2247 [10]
V=wave velocity , <span>f= frequency, </span><span>λ=wavelength </span>
<span>Use it to find corresponding wavelengths for</span><span> f=28 Hz </span>
<span>λ= v/f= 337/28=12.036 m 
</span>
<span>for f=4200 Hz </span>
<span>λ= v/f=337/4200= 0.08 m </span>
<span>So max. wavelength is 12.036 m and </span>
<span>Min Wavelength is 0.08 m </span>
<span>So the range is between .08 m and 12.036 m
</span>Hope this helps. 
4 0
3 years ago
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