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hichkok12 [17]
2 years ago
9

- A certain mass is suspended at one end of a spring of spring-constant of 32,000gm/s2. The

Physics
1 answer:
babunello [35]2 years ago
6 0

Answer: I am pretty sure it is (b) what is the value of mass suspended at the end of the spring.

Explanation:

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Which situation is NOT the result of an unbalanced force acting on an object? A. an object speeds up B. an object maintains spee
7nadin3 [17]
Im pretty sure its b........
5 0
3 years ago
Use the given data to calculate the total mass of hydrogen available for fusion over the lifetime of the sun.
pogonyaev
Total mass of the Sun = 2x10^30kg 

<span>So 76% of that = (2x10^30kg)*(0.76) = 1.52x10^30kg ----> total amount of Hydrogen i</span><span>f only 12% of that is used for fusion, then (1.52x10^30kg)*(0.12) = 1.82x10^9kg</span>
8 0
3 years ago
Is the appearance of a light wave changed as it is aborted?
Sonbull [250]
Light waves are never 'aborted'. 

They can be 'absorbed', and I think that's what you mean. 
It's what happens when light hits something or goes into it,
and never comes out. 

"Absorb" just means "soak up".  When a light wave hits something and
gets soaked up in it, it's gone, and never comes out the other side.

The light wave certainly gets changed ... it no longer exists.

The object that absorbs it also gets changed.  It soaks up the energy
in the light wave, and it has a little more internal energy (heat) than it
had before the light hit it.
7 0
3 years ago
The mass of an object is 4kg and it has a density of 5gcm^-3. what is the volume ​
Andru [333]

Answer:

density =   mass/ volume

5=4000/ volume

volume=4000/5

volume=800 cm^-3

4 0
3 years ago
An older camera has a lens with a focal length of 60mm and uses 34-mm-wide film to record its images. Using this camera, a photo
lesya692 [45]

Answer:

24.71 mm

Explanation:

Distance is proportional to focal length, so

d∝f

which means

\frac{d'_1}{d'_2}=\frac{f_1}{f_2}

Magnification of first lens

M_2=-\frac{d'_1}{d_1}

                   and

M_2=\frac{h'_1}{h_1}

Similarly, magnification of second lens

M_2=-\frac{d'_2}{d_1}

                   and

M_2=\frac{h'_2}{h_1}

From the above equations we get

\frac{M_1}{M_2}=\frac{d'_1}{d_2'}

                   and

\frac{M_1}{M_2}=\frac{h'_1}{h_2'}

which means,

\frac{d'_1}{d_2'}=\frac{h'_1}{h_2'}

and

\frac{d'_1}{d_2'}=\frac{f_1}{f_2}

So, we get

\frac{f_1}{f_2}=\frac{h'_1}{h_2'}\\\Rightarrow f_2=f_1\times\frac{h_2'}{h'_1}\\\Rightarrow f_2=60\times\frac{14}{34}=24.71\ mm

∴ Focal length should this camera's lens is 24.71 mm

6 0
3 years ago
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