Answer:
Decay-the breakdown of dead plants..
Earth- thermal energy comes from deep inside...
Fires- these consume feul...
Explanation:
Here is the complete question.
Benzalkonium Chloride Solution ------------> 250ml
Make solution such that when 10ml is diluted to a total volume of 1 liter a 1:200 is produced.
Sig: Dilute 10ml to a liter and apply to affected area twice daily
How many milliliters of a 17% benzalkonium chloride stock solution would be needed to prepare a liter of a 1:200 solution of benzalkonium chloride?
(A) 1700 mL
(B) 29.4 mL
(C) 17 mL
(D) 294 mL
Answer:
(B) 29.4 mL
Explanation:
1 L = 1000 mL
1:200 solution implies the
in 200 mL solution.
200 mL of solution = 1g of Benzalkonium chloride
1000 mL will be ![\frac{1000mL}{200mL}=\frac{1g}{xg}](https://tex.z-dn.net/?f=%5Cfrac%7B1000mL%7D%7B200mL%7D%3D%5Cfrac%7B1g%7D%7Bxg%7D)
200mL × 1g = 1000 mL × x(g)
x(g) = ![\frac{200mL*1g}{1000mL}](https://tex.z-dn.net/?f=%5Cfrac%7B200mL%2A1g%7D%7B1000mL%7D)
x(g) = 0.2 g
That is to say, 0.2 g of benzalkonium chloride in 1000mL of diluted solution of 1;200 is also the amount in 10mL of the stock solution to be prepared.
∴ ![\frac{10mL}{250mL}=\frac{0.2g}{y(g)}](https://tex.z-dn.net/?f=%5Cfrac%7B10mL%7D%7B250mL%7D%3D%5Cfrac%7B0.2g%7D%7By%28g%29%7D)
y(g) = ![\frac{250mL*0.2g}{10mL}](https://tex.z-dn.net/?f=%5Cfrac%7B250mL%2A0.2g%7D%7B10mL%7D)
y(g) = 5g of benzalkonium chloride.
Now, at 17%
concentrate contains 17g/100ml:
∴ the number of milliliters of a 17% benzalkonium chloride stock solution that is needed to prepare a liter of a 1:200 solution of benzalkonium chloride will be;
= ![\frac{17g}{5g} = \frac{100mL}{z(mL)}](https://tex.z-dn.net/?f=%5Cfrac%7B17g%7D%7B5g%7D%20%3D%20%5Cfrac%7B100mL%7D%7Bz%28mL%29%7D)
z(mL) = ![\frac{100mL*5g}{17g}](https://tex.z-dn.net/?f=%5Cfrac%7B100mL%2A5g%7D%7B17g%7D)
z(mL) = 29.41176 mL
≅ 29.4 mL
Therefore, there are 29.4 mL of a 17% benzalkonium chloride stock solution that is required to prepare a liter of a 1:200 solution of benzalkonium chloride
Hi Jojo
The 4 factors that makes a good fuel are
1) It should be cheap
2)It should not burn too fast or too slowly
3) It should be easily available
4) It should have a high calorific value
I hope that's help !
Answer: mohs picks
Explanation: hope its what you wanted