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sergejj [24]
2 years ago
13

How does a lithium cation compare to a lithium atom?

Chemistry
2 answers:
ExtremeBDS [4]2 years ago
6 0
The correct answer is gonna be C) A lithium cation ion is smaller

A lithium cation has lost its valence electrons, which causes the remaining electrons to be pulled in stronger by the positive charge in the nucleus. As they get closer to the nucleus, the overall size of the atom is decreased.
Assoli18 [71]2 years ago
3 0
The correct answer is c
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Draw all four products obtained when 2-ethyl-3-methyl-1,3-cyclohexadiene is treated with HBr at room temperature and show the me
LenKa [72]

Answer:

See explanation below

Explanation:

In this case we have reaction of addition. In this case a diene reacting with an acid as HBr. This reaction is known as Hydrohalogenation, and, as we have a diene, this kind of reaction can be done as 1,4 addition. Which means that the reaction will be undergoing with an adition in the carbon 1, and carbon 4.

At room temperature we can expect that this reaction can be done in thermodynamic conditions, Now, as the problem states that is forming 4 products, we can expect products of a 1,2 addition too. This product can be formed if the reaction is taking place in the most stable carbocation, and then, by resonance, we can expect the 1,4 product too.

Now, the HBr can be attacked by the double bond of the first position, giving two possible products or by the double bond of the third position giving the other two products. These products are all possible, obviously the most stable will be the major of all of them, but the other three are perfectly possible. One product is formed without doing much, and the other by resonance. Same happens with the other double bond.

In the picture below, you have the mechanism for all the 4 products.

Hope this helps

5 0
2 years ago
What are the basics of chemistry
Novay_Z [31]
In studying chemistry, one should learn how to read the periodic table and periodic trends in the table.. Of course, you should also know the abbreviations of each element in it so that you can identify what element is in chemical structures. Memorizing and knowing it by heart is the best way. You should also study what we call chemical nomenclature which is naming combinations of elements. Elements when combined may form ionic compounds, bonds or acids. Knowing what element reacts with another will also be necessary that's why the concept of chemical reactions must be further studied. 
5 0
3 years ago
When the u-235 nucleus is struck with a neutron, the ce-144 and sr-90 nuclei are produced, along with some neutrons and beta par
butalik [34]
Answer: 2 (2 neutrons are produced).

Explanation:

1) In the left side of the transmutation equationa appears:
²³⁵U + ¹n →

I am omitting the atomic number (subscript to the leff) because the question does not show them as it is focused on number of neutrons.


2) The right side of the transmutation equation has:

→ ¹⁴⁴Ce + ⁹⁰Sr + ?

3) The total mass number of the left side is 235 + 1 = 236

4) The total mass number of Ce and Sr on the right side is 144 + 90 = 234

5) Then, you are lacking 236 - 234 = 2 unit masses on the right side which are the 2 neutrons that are produced along with the Ce and Sr.

The complete final equation is:

²³⁵U + ¹n → ¹⁴⁴Ce + ⁹⁰Sr + 2 ¹n

Where you have the two neutrons produced.
6 0
3 years ago
What is the IUPAC for the compound ZnO?
brilliants [131]
Zinc Oxide is the IUPAC name for ZnO

5 0
3 years ago
What is the density of an object that has a volume of 34.2 cm^3 and a mass of 19.6 g? (a) 0.573 g/cm^3 (b) 1.74 g/cm^3 (c) 670 g
KengaRu [80]

Answer: The density of the object will be 0.573g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of object = 19.6 grams

Volume of object= 34.2cm^3

Putting in the values we get:

Density=\frac{19.6g}{34.2cm^3}=0.573g/cm^3

Thus density of the object will be 0.573g/cm^3

8 0
3 years ago
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