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andriy [413]
3 years ago
11

All isotopes of a particular element have the same atomic number. how then do the isotopes of a particular element differ?

Chemistry
2 answers:
VLD [36.1K]3 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

Isotopes are the species that have same atomic number.

For example, ^{12}_{6}C and ^{13}_{6}C are isotopes. As both of them has 6 protons and there are 6 neutrons in ^{12}_{6}C. There are 7 neutrons in ^{13}_{6}C.

It is known that atomic number is the total number of present in an atom. Whereas mass number is the sum of total number of protons and neutrons present in an atom.

               Atomic mass = no. of protons + no. of neutrons

Therefore, we can conclude that when two elements are isotopes then the isotopes of a particular element differ as they have less or more neutrons.

White raven [17]3 years ago
4 0
They have less or more neutrons. Isotopes have same number of protons but different number of neutrons.
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The amount of silver chromate that precipitates after addition of solutions is 12.44 g.

Number of moles:

The number of moles is the product of molarity of the solution and its volume. The formula is expressed as:

Moles = Molarity x Volume

Calculations:

Step 1:

The molecular formula of silver nitrate is AgNO3. The number of moles of silver nitrate is calculated as:

Moles of AgNO3 = 0.500 M x (150/1000) L

= 0.075 mol

Step 2:

The molecular formula potassium chromate is K2CrO4. The number of moles of potassium chromate is calculated as:

Moles of K2CrO4 = 0.400 M x (100/1000) L

= 0.04 mol

Step 3:

The balanced chemical reaction between AgNO3 and K2CrO4 is:

2AgNO3 + K2CrO4 -----> Ag2CrO4 + 2KNO3

The required number of moles of K2CrO4 = 0.075 mol/2 = 0.0375 mol

The given number of moles of K2CrO4 (0.04 mol) is more than the required number of moles (0.0375 mol). Therefore, AgNO3 is the limiting reagent.

Step 4:

According to the reaction, the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Hence, the number of moles of Ag2CrO4 formed is 0.0375 mol.

The molar mass of Ag2CrO4 is 331.74 g/mol.

The mass of Ag2CrO4 is calculated as:

Mass = 0.0375 mol x 331.74 g/mol

= 12.44 g

Learn more about precipitation here:

brainly.com/question/13859041

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Step 1: List the known quantities and plan the problem.

Known

given: 75.0 g Sn
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Unknown

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