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andriy [413]
3 years ago
11

All isotopes of a particular element have the same atomic number. how then do the isotopes of a particular element differ?

Chemistry
2 answers:
VLD [36.1K]3 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

Isotopes are the species that have same atomic number.

For example, ^{12}_{6}C and ^{13}_{6}C are isotopes. As both of them has 6 protons and there are 6 neutrons in ^{12}_{6}C. There are 7 neutrons in ^{13}_{6}C.

It is known that atomic number is the total number of present in an atom. Whereas mass number is the sum of total number of protons and neutrons present in an atom.

               Atomic mass = no. of protons + no. of neutrons

Therefore, we can conclude that when two elements are isotopes then the isotopes of a particular element differ as they have less or more neutrons.

White raven [17]3 years ago
4 0
They have less or more neutrons. Isotopes have same number of protons but different number of neutrons.
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Compute the freezing point of this solution:
likoan [24]

Answer:

Freezing point = 1.25

Explanation:

If  we increase the concentration of the solution, the concentration of H+ does not change.

Convert 2.5% in to decimal

2.5%  = 2.5 ÷100

        = 0.025

The freezing point = 0.025 × 50

                               = 1.25

8 0
3 years ago
I'm very confused can someone help me please I would really appreciate it
sasho [114]
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7 0
3 years ago
Una muestra de 1 gramo de un elemento contiene 1,5 x 1022 atomos, cual es su masa molar❓❓
marusya05 [52]

El número de Avogadro es 6,022 x 10^23, y es el número de átomos que hay en un mol de dicho elemento. A su vez un mol es la cantidad de un elemento cuya masa en gramos coincide con el peso atómico.

Por tanto, 6,022 x 10^23 átomos del elemento tienen una masa en gramos igual a su peso atómico. Hacemos una regla de tres:


1 gramo -------- 1,5 x 10^22 átomos

x ------------------ 6,022 x 10^23 átomos


=> x = 40,1 gramos por mol del elemento.


De modo que su peso atómico es 40,1. Se trata del calcio.


Saludos.

7 0
3 years ago
A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L.A. If the contai
marta [7]

Answer:

Approximately 6.81 × 10⁵ Pa.

Assumption: carbon dioxide behaves like an ideal gas.

Explanation:

Look up the relative atomic mass of carbon and oxygen on a modern periodic table:

  • C: 12.011;
  • O: 15.999.

Calculate the molar mass of carbon dioxide \rm CO_2:

M\!\left(\mathrm{CO_2}\right) = 12.011 + 2\times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

Find the number of moles of molecules in that 41.1\;\rm g sample of \rm CO_2:

n = \dfrac{m}{M} = \dfrac{41.1}{44.009} \approx 0.933900\; \rm mol.

If carbon dioxide behaves like an ideal gas, it should satisfy the ideal gas equation when it is inside a container:

P \cdot V = n \cdot R \cdot T,

where

  • P is the pressure inside the container.
  • V is the volume of the container.
  • n is the number of moles of particles (molecules, or atoms in case of noble gases) in the gas.
  • R is the ideal gas constant.
  • T is the absolute temperature of the gas.

Rearrange the equation to find an expression for P, the pressure inside the container.

\displaystyle P = \frac{n \cdot R \cdot T}{V}.

Look up the ideal gas constant in the appropriate units.

R = 8.314 \times 10^3\; \rm L \cdot Pa \cdot K^{-1} \cdot mol^{-1}.

Evaluate the expression for P:

\begin{aligned} P &=\rm \frac{0.933900\; mol \times 8.314 \times 10^3 \; L \cdot Pa \cdot K^{-1} \cdot mol^{-1} \times 298\; K}{3.4\; L} \cr &\approx \rm 6.81\times 10^5\; Pa \end{aligned}.

Apply dimensional analysis to verify the unit of pressure.

4 0
3 years ago
What’s the symbol of the element that has 8 protons, 9 neutrons, and 8 electrons
Katena32 [7]

Answer:

oxygen

Explanation:

 The given isotope has 8 protons and 8 electrons, so the atomic number of the given isotope is 8, which is the atomic number of oxygen.

7 0
3 years ago
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