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Kaylis [27]
3 years ago
10

Which always yields a cross section that is the same shape and size as the base of the figure?

Mathematics
2 answers:
Ugo [173]3 years ago
5 0
The best answer would be c. because the cross section would make the shape and the dimension of the shape. hope this help*)
avanturin [10]3 years ago
5 0

Answer:

The correct answer is:

C.) A triangular prism when sliced parallel to its base.

Step-by-step explanation:

We know that a triangular prism consists of 2 triangular shapes and three rectangular shapes.

  • We know that we can never obtain a cross-section similar to the base when the slicing is done perpendicular to it's base.
  • We know that when we slice a triangular pyramid parallel to the base than we will obtain a triangle of smaller dimensions.
  • But when we slice a triangular prism parallel to the  base than we obtain a cross-section that is similar to the base of a triangular prism.

Hence, the correct answer is Option: C)

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What is the range of the following exponential function?plz help asap
IrinaVladis [17]

Answer:

0.23

Step-by-step explanation:

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3 years ago
The area of the triangle below is 2/5 square foot what is tge lenght in feet of the base of the triangle
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motikmotik
The answer is C hope this helped:)
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4 years ago
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12 Rose and Haydn share £250 in the ratio 2:3
dalvyx [7]

Answer:

Amount = £37

Step-by-step explanation:

Let Rose be represented by R.

Let Haydn be represented by H.

Given the following data;

Total amount = £250

Ratio of R:H = 2:3 = 2 + 3 = 5

To find how much Rose earned;

R = 2/5 * 250

R = 500/5

R = £100.

For Haydn;

H = 3/5 * 250

H = 750/5

H = £150

Next, we calculate the amount Haydn gave to charity;

Percent = 42% = 42/100 = 0.42

H = 0.42 * 150

H = £63

To find how much more Rose gave to charity than Haydn;

Amount = R - H

Amount = 100 - 63

Amount = £37

8 0
3 years ago
The strength of an aluminum alloy is normally distributed with mean 10 gigapascals (GPa) and standard deviation 1.4 GPa. What is
tensa zangetsu [6.8K]

Answer:

The first quartile of the strengths of this alloy is 9.055 GPa.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The strength of an aluminum alloy is normally distributed with mean 10 gigapascals (GPa) and standard deviation 1.4 GPa.

This means that \mu = 10, \sigma = 1.4

What is the first [lower] quartile of the strengths of this alloy?

This is the 100/4 = 25th percentile, which is X when Z has a pvalue of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 10}{1.4}

X - 10 = -0.675*1.4

X = 9.055

The first quartile of the strengths of this alloy is 9.055 GPa.

3 0
3 years ago
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