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2 years ago

Write 0.1 as a fraction

Mathematics

2 answers:

Lelu [443]2 years ago

6 0

Answer:

1/10

Step-by-step explanation:

Alla [95]2 years ago

4 0

Answer:

1/100

Step-by-step explanation:

I hope this is right :l mmmmmmmmmmmmmmmmmm

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if 3 over 4 ton of pebbles covers 4 over 5 of a garden, how many tons of pebbles are required to cover the entire garden?

natta225 [31]

(3/4) /(4/5) = x/1
cross multiply
4/5x = 3/4
x = 3/4 * 5/4
x = 15/16 tons of pebbles are needed to cover the entire garden

5 0

2 years ago

Read 2 more answers

How much money would a person have 8 years after they invested $2,000 into an account that has an annual interest rate of 3% tha

madam [21]

The amount of money the person would have in 8 years s $2541.74.

<h3>How much would the person have in 8 years? </h3>

The formula for calculating future value is:

FV = P (1 + r)^nm]

Where:

FV = Future value

P = Present value = $2000
R = interest rate = 3% / 12 = 0.25%
m = number of compounding = 12
N = number of years = 8 years

Value of the account in 8 years with monthly compounding = $2000(1.0025)^(12 x 8) = $2541.74

To learn more about future value, please check: brainly.com/question/18760477

4 0

1 year ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

2 years ago

You are constructing deck chairs that require 12 2/3 feet of lumber each. How many feet of lumber will you use to make 15 chairs

Mrrafil [7]

As each chair needs 12.6667 feet lumber.So 15 chairs will need 15*12.6667=190.0005 lumber

5 0

2 years ago

How do u work out (2¾)²

Sergeu [11.5K]

You would do 2^2 and will come out to 4. Your mixed number is 4. Then you will do 3/4^2 and will come out to 9/12 Your answer is 4 9/12

8 0

3 years ago

Write 0.1 as a fraction​

Write 0.1 as a fraction