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Varvara68 [4.7K]
3 years ago
12

What is the solution to this equation?

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

D. x=12

Step-by-step explanation:

Add 17 to the other side of the equal sign

x=17+5

Then add 17 and -5

X=12

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One pen is chosen without looking from a bag that has 3 blue pens, 6 red pens, and 3 green pens.
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The probability of choosing. a green pen is 0.25

<h3>What is probability?</h3>

Probability is the likelihood or chance that an  event will occur. Mathematically;

Probability = Expected/Total outcome

If a bag has 3 blue pens, 6 red pens, and 3 green pens, then;

Total pen = 3+6+3

Total pen = 12

If a green pen is chosen, then

Pr(choosing a green pen) = 3/12

Pr(choosing a green pen) = 0.25

Hence the probability of choosing. a green pen is 0.25

Learn more on probability here: brainly.com/question/25870256

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Coordinates will show the vertices of the triangle, and using the vertices, calculate length of the sides of the triangle.With the side length you can now calculate the angles of the triangle.

Step-by-step explanation:

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5 0
3 years ago
70 POINTS!!!!!!!!!! Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ
Likurg_2 [28]

Answer:

The measures of angles of triangle EFQ are

1) m\angle EFQ=100\°

2) m\angle FEQ=66\°

3) m\angle EQF=14\°

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

m\angle DFQ=\frac{1}{2}(arc\ QD)

substitute the given value

10\°=\frac{1}{2}(arc\ QD)

20\°=(arc\ QD)

arc\ QD=20\°

step 2

Find the measure of arc FQ

we know that

arc\ QD+arc\ FQ+arc\ EF=180\° ---> because ED is a diameter (the diameter divide the circle into two equal parts)

substitute the given values

20\°+arc\ FQ+28\°=180\°

arc\ FQ=180\°-48\°=132\°

step 3

Find the measure of angle EFQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EFQ=\frac{1}{2}(arc\ QD+arc\ ED)

substitute the given value

m\angle EFQ=\frac{1}{2}(20\°+180\°)=100\°

step 4

Find the measure of angle FEQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle FEQ=\frac{1}{2}(arc\ FQ)

substitute the given value

m\angle FEQ=\frac{1}{2}(132\°)=66\°

step 5

Find the measure of angle EQF

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EQF=\frac{1}{2}(arc\ EF)

substitute the given value

m\angle EQF=\frac{1}{2}(28\°)=14\°

5 0
4 years ago
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