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lions [1.4K]
3 years ago
11

sam bought some toys. he bought a baseball for $9.48 and paid 6.46 on marbles with a $20 bill. how much change from the purchase

Mathematics
2 answers:
nikdorinn [45]3 years ago
7 0
$15.94 is the cost of the baseball and marbles together and subtracted from zero, i believe it should be $4.06
Tasya [4]3 years ago
6 0
He would have paid $15.94 and since he’s paying with a $20 bill, all you would do is subtract $15.94 from $29. This leaves us $4.06.
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Each side of a square is increased by 3 inches. The perimeter of the new square is 40 inches more than twice the length of the s
RUDIKE [14]

Length of side of new square is 17 inches

Step-by-step explanation:

  • Step 1: Let the length of the side of the old square be x. Then length of side of new square = x + 3 and Perimeter of new square = 40 + 2x

Perimeter of a square = 4 × side

⇒ 4(x + 3) = 40 + 2x

⇒ 4x + 12 = 40 + 2x

⇒ 2x = 28

⇒ x = 14 inches

  • Step 2: Find length of side of the new square

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3 years ago
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ElenaW [278]

Answer:

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Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

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Answer:

Mean:6

Mad:2.29

Step-by-step explanation:

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