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9514 1404 393
Answer:
106
Step-by-step explanation:
Each of the whole numbers could be 4 greater than the value it is rounded down to. Then the maximum original sum is ...
90 +4 +4 +4 +4 = 106
__
<em>Example</em>
The numbers could be 14, 24, 34, 34. Their rounded values are 10, 20, 30, 30, for a total of 90. The total of the original numbers is 106.
Answer:
The value of the slope in this equation is 50
The interpretation is that the rate of change in the cost of the phone bill per unit change in gigabytes of data used each month is 50
Step-by-step explanation:
To answer this question, we need to compare the given equation with the equation of a straight line graph.
The equation we have is;
c = 50g + 75
comparing this with the equation of a straight line, we have
y = mx + c
where m represents the slope and c is the y-intercept
So comparing both, the slope of the equation is 50.
The slope is always the co-efficient of the value on the x-axis
So what does this mean?
The slope also called the gradient represents the rate of change of the y-term divided by the rate of change of the x-term. In simpler terms, when we talk of the slope, we mean the rate of change of the y term per the unit change of the x-term.
So what we mean in this case is the rate of change in cost of the phone bill per unit change in gigabytes of data used each month is 50
Answer:
.82
Step-by-step explanation:
45.75 x .018=.82
Answer:
7.86 km
Step-by-step explanation:
Let x represent the distance point P lies east of the refinery. (We assume this direction is downriver from the refinery.)
The cost of laying pipe to P from the refinery (in millions of $) will be ...
0.5√(1² +x²)
The cost of laying pipe under the river from P to the storage facility will be ...
1.0√(2² +(9-x)²) = √(85 -18x +x²)
We want to minimize the total cost c. That total cost is ...
c = 0.5√(x² +1) +√(x² -18x +85)
The minimum value is best found using technology. (Differentiating c with respect to x results in a messy radical equation that has no algebraic solution.) A graphing calculator shows it to be at about x ≈ 7.86 km.
Point P should be located about 7.86 km downriver from the refinery.
