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Viefleur [7K]
3 years ago
9

Ignore the answer thing it’s an scavenger hunt

Mathematics
2 answers:
Darya [45]3 years ago
6 0

Answer:

I don't really understand the question but if the question means simplify then for question 9 the answer is 19x.

Question number 10 is x + 4x - 24.

Step-by-step explanation:

x is outside the brackets but they multiply with each number inside so there question is broken down to : 3x + 5x + 11x then you add everything which is 19x.

If you didn't know, x is not added to 4x because it's a plus not multiply. Variables ( letters) only add if it's multiplication.

hope this helps

Nikolay [14]3 years ago
5 0

Answer: 19x is the first answer 5x - 24 is the second answer

Step-by-step explanation:

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Create a real-life representation of the following multiplication problem. Explain what the result represents in the problem.
olya-2409 [2.1K]

The real-life problem will be:- The total number of chocolates is 24 and there are 3 boxes what will be the number of chocolates filled in each box. The number of chocolates in each box will be 8.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The given expression is:-

24\times \dfrac{1}{3} = 8

The real-life problem will be given the as:-The total number of chocolates is 24 and there are 3 boxes what will be the number of chocolates filled in each box. The number of chocolates in each box will be 8.

Hence the number of chocolates in each box will be 8.

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7 0
1 year ago
Pls help with these 4 questions!
sergejj [24]

Answer:

It is A.

Step-by-step explanation:

also, this is one question. A, B, C and D are just answers.

3 0
3 years ago
Read 2 more answers
How to solve the problem
Dima020 [189]
A=1 B=2 C=3 Yes it would work for all because its using the commutative property.
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3 years ago
What is the correct first step to solve this system of equations by elimination?
storchak [24]

\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

  • <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

Hence, The value of x and y is 2 and 10/3

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