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bekas [8.4K]
3 years ago
3

An iodine-clock kinetics experiment was performed by varying the composition of reactant solutions and measuring the resulting r

ates of reaction. 1st column: Reactant solution A; Reactant solution B; Time to complete reaction2nd column ‘Trial 1’: 10.0 mL I-(aq), 5.0 mL S2O2-3(aq); 10.0 mL I-(aq)5.0 mL S2O2-3(aq); 10 seconds3rd column ‘Trial 2’: 5.0 mL I-(aq)5.0 mL S2O2-3(aq); 10.0 mL S2O2-8(aq)1.0 mL starch(aq); 20 seconds4th column ‘Trial 3’: 5.0 mL S2O2-8(aq) 1.0 mL starch(aq); 10.0 mL S2O2-8(aq)1.0 mL starch(aq); 20 seconds How do Trials 2 and 3 in the above table differ? a. Trial 2 has half as much starch as Trial 3. b. Trial 2 has twice as much I- as Trial 3. c. Trial 3 has twice as much S2O2-8 as Trial 2. d. Trial 3 has half as much S2O2-3 as Trial 2. Four mechanisms have been proposed to explain the results in the table. Mechanism 1: I-(aq)+I-(aq)->I2-2(aq) (slow) I2-2(aq)+S2O2-8(aq)->I2(aq)+SO2-4(aq)(fast) Mechanism 2: I-(aq)+S2O2-8(aq)->[S2O8∙I]3-(aq) (slow) [S2O8∙I]3-(aq)+I-(aq)->I2(aq)+2SO2-4(aq) (fast) Mechanism 3: I-(aq)+S2O2-8(aq)<->[S2O8∙I]3-(aq) (fast) [S2O8∙I]3-(aq)+I-(aq)->I2(aq)+2SO2-4(aq) (slow) Mechanism 4: 2I-(aq)+S2O2-8(aq)->I2(aq)+2SO2-4(aq) Of the proposed mechanisms, which would be supported by the results in the table? Mechanism 1 Mechanism 2 Mechanism 3 Mechanism 4
Chemistry
1 answer:
nydimaria [60]3 years ago
6 0

it would be 826483916-873928+379 divided by 7253 which is 872538^19

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Ok let me explain the procedure to you:
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2 years ago
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Answers and Explanations:

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Here, physical properties are:

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