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2 years ago

What is the general formula for cycloalkenes.

Chemistry

2 answers:

maria [59]2 years ago

3 0

C( n)H(2n) is the general formula, eg: Cyclohexane is C6H12

dexar [7]2 years ago

3 0

$\tt \huge { \red{\colorbox{lime}{Answer}}}$

$\tt \bf \: \implies C_{n}H_{2}n$

Cycloalkenes have the general formula

$\\ \tt \: \: \: C_{n} H_{2} \: _{n - m}$

The letter m represents the number of double bonds. Thus, cyclopropene has the formula C3H4 while that of cyclobutene is C4H6. The properties of alkanes and alkenes are very similiar.

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The voltage generated by the zinc concentration cell described by the line notation Zn ( s ) ∣ ∣ Zn 2 + ( aq , 0.100 M ) ∥ ∥ Zn

Oxana [17]

Answer:

0.193 M

Explanation:

We need to calculate the Zn²⁺ concentration at the cathode where reduction occurs which is the right side in the expression:

Zn2+(aq,0.100 M) ‖ Zn2+(aq,? M) | Zn(s)

Zn²⁺ (aq,?) + 2 e⁻ ⇒ Zn (s)

and oxidation will occur in the anode

Zn (s) ⇒ Zn²⁺ (aq, 0.100 M ) + 2 e⁻

and the overall reaction is

Zn²⁺ (aq,?) ⇒ Zn²⁺ (0.100 M )

The driving force is the difference in concentration and E the electromotive force will be given by

E = Eº - 0.0592/2 log [Zn²⁺ (0.100 M) / Zn²⁺ (M) ]

Plugging the value for E and knowing Eº is cero because we have the same electrodes, we have

17.0 x 10⁻³ = 0 - 0.0592 log 0.100/ X =

- 17.0 x 10⁻³ / 0.0592 = log 0.100 / X

- 0.287 = log (0.100 / X)

Taking inverse log to both sides of the equation

0.516 = 0.100 / X ⇒ X = 0.100 / 0.516 = 0.193 M

4 0

3 years ago

1.42 mol sample of neon gas at a temperature of 13.0 °C is found to occupy a volume of 25.5 liters. The pressure of this gas sam

Dima020 [189]

Answer: 996 mmHg

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = ?

V= Volume of the gas = 25.5 L

T= Temperature of the gas = 13°C = (273+13) K = 286K

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= 1.42

$P=\frac{nRT}{V}=\frac{1.42\times 0.0821\times 286}{25.5}=1.31atm=996mmHg$ (760mmHg=1atm)

Thus pressure of this gas sample is 996 mm Hg.

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3 years ago

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Valentin [98]

When the volume is 450 cm3 so the boat will displace 450 g.

so we have 450 g - 14.5g = 435.5 left

so to get how many pennies can be added to the boat before it sinks can be determined by:

divided the mass for the one penny:

no.of Penny = 435.5 / 2.5g

= 174.2

∴ the boat will float with 174 pennies and will start to sink with 175

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