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2 years ago

8

What is the general formula for cycloalkenes.

2 answers:

maria [59]2 years ago

3 0

C( n)H(2n) is the general formula, eg: Cyclohexane is C6H12

dexar [7]2 years ago

3 0

$\tt \huge { \red{\colorbox{lime}{Answer}}}$

$\tt \bf \: \implies C_{n}H_{2}n$

Cycloalkenes have the general formula

$\\ \tt \: \: \: C_{n} H_{2} \: _{n - m}$

The letter m represents the number of double bonds. Thus, cyclopropene has the formula C3H4 while that of cyclobutene is C4H6. The properties of alkanes and alkenes are very similiar.

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HELP ASAP!!! Which two energy transformations are shown in the photo? A. Chemical energy → electromagnetic energy B. Chemical en

diamong [38]

Answer:

Chemical energy _ thermal energy

4 0

2 years ago

Read 2 more answers

What is the density of carbon dioxide gas if 0.196g occupies a volume of 100mL?

-BARSIC- [3]

We know that the equation for density is:

$D=\frac{m}{V}$

where D is the density, m is the mass in grams, and V is the volume.

Given two of the variables, we can then solve for density:

$D=\frac{0.196g}{100mL}= \frac{0.00196g}{mL}$

So therefore, we now know that the density of carbon dioxide gas is 0.00196g/mL.

7 0

2 years ago

a chemist adds of a calcium bromide solution to a reaction flask. calculate the mass in grams of calcium bromide the chemist has

mestny [16]

The mass of Calcium bromide added in the flask is 29.7 g.

<h3>What is Molarity? </h3>

Molarity is defined as the ratio of number of moles od solute to the number of volume of solution in litres.

Molarity = number of moles/ volume

<h3>Calculation of Moles</h3>

Number of moles = Molarity × volume

Given,

Molarity of Calcium bromide = 0.363 M

Volume of Calcium bromide = 410 mL

= 0.410L

By substituting all the value, we get

Number of moles = 0.363 × 0.410

= 0.148 mol

As we know that,

Molar mass of Calcium bromide = 199.89 g

<h3>What is Mole? </h3>

Mole is defined as the given mass of substance to the molar mass of substance.

Given mass = Moles × Molar mass

= 0.148 × 199.89

= 29.75 g

= 29.7 g (significant digit)

Thus, we calculated that the mass of Calcium bromide added in the flask is 29.7 g.

learn more about Molarity:

brainly.com/question/19517011

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DISCLAIMER:

The above question is incomplete. Below is the complete question

A chemist adds 410.0mL of a 0.363 M calcium bromide solution to a reaction flask. calculate the mass in grams of calcium bromide the chemist has added to the flask. round your answer to 3 significant digits.

4 0

1 year ago

Must show units and how they cancelli 1.) 175 km to um 3.) 385 nm to dm 5.) 492 um tom 7.) 52 x 103 dm to mm 9.) 321x 1035 mm to

morpeh [17]

Explanation:

1.) 175 km to μm

$1 km=10^9 \mu m$

$175 km=175\times 10^9\mu m=1.75\times 10^{11} \mu m$

3.) 385 nm to dm

$1 nm=10^{-8} dm$

$385 nm=385\times 10^{-8} dm=3.85\times 10^{-6} dm$

5.) 492 μm to m

1 μm = $10^{-6} m$

$492 \μm=492\times 10^{-6} m=4.92\times 10^{-4} m$

7.) $52\times 10^3$ dm to mm

1 dm = 100 mm

$52\times 10^3 dm=52\times 10^3\times 100 mm=5.2\times 10^{6}dm$

9.) $321\times 10^{35}$ mm to km

$1 mm = 10^{-6} km$

$321\times 10^{35} mm=321\times 10^{35}\times 10^{-6} km=3.21\times 10^{31} km$

11.) $456\times 10^3$ m to km

m = 0.001 km

$456\times 10^3m =456\times 10^3 m\times 0.001 km=456 km$

13.) $422\times 10^3$ m to nm

$1 m = 10^{9} nm$

$422\times 10^3 m=422\times 10^3\times 10^{9} nm=4.22\times 10^{14} nm$

15.) $4.87\times 10^{30}$ m to pm

$1 m = 10^{12} pm$

$4.87\times 10^{30} m=4.87\times 10^{30}\times 10^{12} pm=4.82\times 10^{42} pm$

17.) $5.26\times 10^3$ m to um

1 m = $10^{6} \mu m$

$5.26\times 10^3 m=5.26\times 10^3\times 10^6 \mu m=5.26\times 10^{9} \mu m$

19.) $1.25\times 10^{35}$ m to Mm

1 m = $10^{-6} Mm$

$1.25\times 10^{35} m=1.25\times 10^{35}\times 10^{-6} Mm=1.25\times 10^{-29} Mm$

21.) $4.22\times 10^3$ Tm to nm

$1 Tm = 10^{21} nm$

$4.22\times 10^3 Tm=4.22\times 10^3\times 10^{21} nm=4.22\times 10^{24} nm$

6 0

3 years ago

How many lone pairs of electrons in lewis structure of CH3 OH

Brums [2.3K]

There would be 2 which would be on the oxygen

4 0

2 years ago