Answer:
Kw = 1×10⁻¹⁴
Explanation:
The product between the [H₃O⁺] . [OH⁻] talks about the
autoionization of water.
2H₂O ⇄ H₃O⁺ . OH⁻ Kw
This is an equilibrium of 2 molecules of water that produces 1 mol of hydronium and 1 mol of hydroxides.
In order to determine pH and pOH, parameters to indicate acidic or basic solutions we know:
- log [H₃O⁺] = pH
- log [OH⁻] = pOH
When [H₃O⁺] or [OH⁻] = 1×10⁻⁷ , pH or pOH = 7 (Neutral solutions)
So if we see the equation above, we have an equilibrium.
In order to determine Kw, we need [H₃O⁺] . [OH⁻]
As [H₃O⁺] and [OH⁻] = 1×10⁻⁷ , Kw = 1×10⁻¹⁴
