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3 years ago

Solve the absolute value eaquation

Mathematics

1 answer:

Nostrana [21]3 years ago

4 0

I think the answer is x= 33, -7

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Find the area of each shape, please help and I will give a lot points

Alex73 [517]

Answer:

15. Area of parallelogram = bh

b = 9m

h = 4m

a = 9*4 = 36m^2

You can also use the rectangle property here.

a = l*b

l = 9

b = 6

a = 9*6 = 54 m^2

Though I would prefer the first one better.

16. Area of triangle = 1/2*bh

b = 17m

h = 3

a = 17*3/2 = 51/2 = 25.5m^2

18. Area of a trapezium = a+b/2*h (a and b are two parallel sides and h the height)

a = 15

b = 7

h = 15

a = 15+7/2*15 = 22/2*15 = 11*15 = 165m^2

19. Area of triangle = 1/2*bh

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h = 7

a = 24*7/2 = 168/2 = 84

Hope u understood

Please mark as brainliest

Thank You

5 0

2 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of $y$ in equation (1) we get:

$x=333-y\\\\x=333-145\\\\x=188.$

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

4 0

3 years ago