Y=1-2x
-4x+3y=-17
Plug in y into -4x+3y=-17
-4x+3 (1-2x)=-17
-4x+3-6x=-17
-10x+3=-17
-3 both sides
-10x=-20
÷-10 both sides
x=2
plug in x to find y
y=1-2 (2)
y=1-4
y=-3
x+3y=9
2x+3y=15
make first equation into x= form
-3y both sides
x=-3y+9
2x+3y=15
plug in x into 2x+3y=15
2 (-3y+9)+3y=15
-6y+18+3y=15
-3y+18=15
-18 both sides
-3y=-3
÷-3 both sides
y=1
plug in y
x+3 (1)=9
x+3=9
-3 both sides
x=6
Answer:
The answer to your question is letter C
Step-by-step explanation:
(x² - 5x) + (2x² + 2x - 5)
Process
1.- Remove parenthesis without changing the sign of the terms
x² - 5x + 2x² + 2x - 5
2.- Simplify like terms
(x² + 2x²) + (-5x + 2x) - 5
3.- Result
3x² - 3x - 5
she had 27 students after 5 students left her class.
Her present number of student = 27
Initial number of student before 5 left the class = 27 + 5 = 32
number of student in his class before the 5 student left can be represented as follows
where
b = number of student before 5 student left his class
b - 5 = 27
