Find the range of f given the domain<br> = {-2, 0, 5, 9}

The area of rectangle A is double the area of rectangle B explain your answer

dybincka [34]

A's area is 4x3=12, B=2x3=6, so yes, A is twice the area of B

a Answer: YES

b Answer: One side doubled, the other stayed the same, so area doubled.

4 0

3 years ago

The fit line equation is Y = -2.61x +152.51, where x is variable 1 and Y is variable 2. According to the equation, what is the e

egoroff_w [7]

The expected value of y when x is equals to 45 in the equation is 35.06

<h3>How to find variable from an equation?</h3>

The equation is given as follows;

y = -2.61x + 152.51

where

x = variable 1
y = variable 2

Therefore,

when

x = 45

y = -2.61x + 152.51

y = -2.61(45) + 152.51

y = - 117.45 + 152.51

y = 35.06

learn more on equation here: brainly.com/question/14279419

#SPJ1

5 0

2 years ago

PLEASE ANSWER!!!!!! WILL MARK BRAINLIEST!!!!!!

docker41 [41]

Answer:

sinB= 3/5, tanA=4/3, cosB=4/5

Step-by-step explanation:

5 0

3 years ago

What is does a equal

Blababa [14]

Answer:

<u>a = 13</u>

Step-by-step explanation:

We should know that: The sum of the interior angles of the triangle = 180°

Given the measure of the angles: (6a - 2) , (5a - 13) and (5a - 13)

So,

(6a - 2) + (5a - 13) + (5a - 13) = 180°

16 a - 28= 180 ⇒ Add 28 to both sides

16 a = 180 + 28 = 208 ⇒ Divide both sides by 16

a = 208/16 = 13

5 0

3 years ago

A nationwide study of American homeowners revealed that 65% have one or more lawn mowers. A lawnequipment manufacturer, located

GenaCL600 [577]

Answer:

$z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589$

$p_v =P(z>1.589)=0.056$

If we compare the p value obtained with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

Step-by-step explanation:

Data given and notation

n=497 represent the random sample taken

X=340 represent the homes in Omaha with one or more lawn mowers

$\hat p=\frac{340}{497}=0.684$ estimated proportion of homes in Omaha with one or more lawn mowers

$p_o=0.65$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the true proportion of homes in Omaha with one or more lawn mowers is higher than 0.65.:

Null hypothesis: $p\leq 0.65$

Alternative hypothesis: $p > 0.65$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.589)=0.056$

If we compare the p value obtained with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

7 0

3 years ago

Find the range of f given the domain = {-2, 0, 5, 9}