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Alja [10]
3 years ago
8

Help with this task it's confusing can u explain how you got the answer

Mathematics
1 answer:
Andru [333]3 years ago
7 0
Oh my goodness !  You were doing such an absolutely beautiful job,
as far as you went, but then you ran into some rough road and quit.

You've got the correct expressions for the ages of the three people:

-- Will . . . w
-- Ben . . . w+3
-- Jan . . . 2(w+3)
You slipped up when you expanded Jan's age:  2(w+3) = <u>2w + 6</u> ,
and it was all down hill from there.

Let's do it again, together:

-- Will . . . w
-- Ben . . . w + 3
-- Jan . . . 2w + 6

Total:  (w + w + 2w) + (3 + 6) = 4w + 9

So the equation is:    <em><u>4w + 9 = 41</u></em>
Now you're supposed to solve it.

Subtract 9 from each side:   4w  =  32

Divide each side by 4:        <u>w = 8</u>

-- Will = w . . . . . 8 y.o.
-- Ben = w+3 . . . 11 y.o.
-- Jan = 2(w+3) . . 22 y.o.

When will Jan be twice as old as Will ?
That'll happen in 'x' years.
At that time, Will will be (8+x) and Jan will be (22+x),
and her age will be double Will's age.

22 + x  =  2(8 + x)

22 + x  =  16 + 2x

Subtract 'x' from each side:    22  =  16 + x

Subtract  16  from each side:  <em>  6 = x</em>

<u>Check:</u>

In 6 years, Jan will be (22+6) = 28,
and Will will be (8+6) = 14 .

28 = twice as old as 14.      yay!

Can I make a little suggestion ?
I'm going to make it anyway:

Your problem was neatness.
You were doing great work in that big open space on the sheet, but it
started to get ragged.  When you tried to look back to see if you made
a mistake, you couldn't find it in the mess.
This is not an easy problem, but you definitely know your stuff. 
I think if you keep it a little neater, you're going to sparkle !
You might be interested in
Please help me solve what is on that document
In-s [12.5K]

The most misleading graph is graph B because the blue rectangle and the red rectangle do not have the same width when plotted on the same scale

<h3>The ratio of the median weekly earnings</h3>

From the graph, we have the median weekly earnings to be:

  • High school diploma = $750
  • Bachelor's degree = $1250

So, the ratio is:

Ratio = $750 : $1250

Simplify

Ratio = 3 : 5

Hence, the ratio of the median weekly earnings is 3 : 5

<h3>The ratio of the area of the red rectangle to the blue rectangle in graph A?</h3>

In (a), we have:

Ratio = 3 : 5

The scale on the horizontal axis is given as:

1 unit per grid mark

Both rectangles have a width of 1 unit.

So, we have:

Ratio = 3 * 1: 5 * 1

Simplify

Ratio = 3 : 5

Hence, the ratio of the area of the red rectangle to the blue rectangle in graph A is 3 : 5

<h3>The ratio of the area of the red rectangle to the blue rectangle in graph B?</h3>

In (a), we have:

Ratio = 3 : 5

The scale on the horizontal axis is given as:

1 unit per grid mark

The red rectangle has a width of 3 units, while the blue has 5 units as its width

So, we have:

Ratio = 3 * 3 : 5 * 5

Simplify

Ratio = 9 : 25

Hence, the ratio of the area of the red rectangle to the blue rectangle in graph B is 9 : 25

<h3>The ratio of the volume of the red cube to the blue cube in graph C?</h3>

In (a), we have:

Ratio = 3 : 5

The scale on the horizontal axis is given as:

1 unit per grid mark

The red rectangle has a width of 3 units, while the blue has 5 units as its width.

Since the base are squares, we have:

Ratio = 3 * 3  * 3 : 5 * 5 * 5

Simplify

Ratio = 27 : 125

Hence, the ratio of the volume of the red cube to the blue cube in graph C is 27 : 125

<h3>The most misleading graph</h3>

The most misleading graph is graph B.

This is so because the blue rectangle and the red rectangle do not have the same width when plotted on the same scale

Read more about bar charts at:

brainly.com/question/24741444

#SPJ1

7 0
2 years ago
Please help!! MathsWatch, Surd Expressions, Clip 207c
dexar [7]

Answer:

A=(72+36\sqrt{3})\ mm^2

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

b=AB+BC+CD+DE ----> by segment addition postulate

substitute

b=3+3+3+3=12\ mm

step 2

Find the height of rectangle

a=FB+CG+GH ---> by segment addition postulate

substitute the given values

a=3+CG+3\\a=6+CG

Find the length sides CG

Applying the Pythagorean Theorem

BG^2=BC^2+CG^2

substitute the given values

6^2=3^2+CG^2

CG^2=6^2-3^2

CG=\sqrt{27}\ mm

simplify

CG=3\sqrt{3}\ mm

therefore

a=(6+3\sqrt{3})\ mm

step 3

Find the area of rectangle

A=ab

we have

a=(6+3\sqrt{3})\ mm

b=12\ mm

substitute

A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2

8 0
3 years ago
Question 2:
Margarita [4]

POOPY HEAD ATE THE RELATIONSHIP

5 0
3 years ago
A(n) = 1 + (n –1)(–5.7)
hammer [34]
Im guessing this is simplify so the answer would be 

<span><span>−<span>5.7n</span></span>+6.7</span><span>n
</span>__________
         n
6 0
3 years ago
If you have a two digit divisor in a three digit David and does the cushion always have to be have the same number of digits
Mariulka [41]
No because a 2 digit divisor always has less digits than a 3 digit divisor
4 0
3 years ago
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