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Doss [256]
3 years ago
7

A solenoid is built with 870 turns uniformly distributed over a length of 0.390 m to produce a magnetic field of magnitude 1.00

× 10−4 T at its center. What is current necessary for this to happen? 17.4 mA
Physics
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

35.7 mA

Explanation:

The magnetic field inside a solenoid is given by:

B=\mu_0 I n (1)

where

\mu_0 = 4\pi \cdot 10^{-7} H/m is the vacuum permeability

I is the current

n is the number of turns per unit length

Since we have

N = 870 turns

L = 0.390 (length of the solenoid)

we can calculate n

n=\frac{N}{L}=\frac{870}{0.390}=2230.8

And now we can re-arrange eq.(1) to find the current, I:

I=\frac{B}{\mu_0 n}=\frac{1.00\cdot 10^{-4} T}{(4\pi\cdot 10^{-7} H/m)(2230.8m^{-1})}=0.0357 A = 35.7 mA

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Complete Question

In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 130 m above the water. If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?

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Explanation:

From the question we are told that

   The height at which he let go of the brief case is  h =  130 m  

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