Question

An object has a kinetic energy of 14 J and a mass of 17 kg , how fast is the object moving?

Answer 1

Answer:

velocity = 1.28 meter per second

Explanation:

$k.e. = \frac{1}{2} \times m \times {v}^{2}$

( where, k.e. = kinetic energy , m = mass , v = velocity )

so,

=》

$14 = \frac{1}{2} \times 17 \times v {}^{2}$

=》

$\frac{28}{17} = v {}^{2}$

=》

$v = \sqrt{1.64}$

=》

$v = 1.28 \: ms {}^{ - 1}$

Answer 2

Use the formula:

E = (1/2) * m * v ^2

For unit consistency, make sure that:

E energy is in joules (J)
m mass is in kilograms (kg)
v velocity is in meters per second (m/s)
So, substituting to the equation:

14= (1/2) * (17) * v^2

By algebraic manipulation, we derive:

v = (2*14/17)^0.5

v = 1.2834 m/s
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