What are the solutions of -x^2+4x=x-4
1 answer:
Answer:
x = -1 and x = 4
Step-by-step explanation:
Step 1: Get everything to one side of the equation so it's set equal to zero..
-x² + 4x = x - 4 becomes...
-x² + 3x + 4 = 0 (subtract x and add 4 to both sides)
x² - 3x - 4 = 0 (divide both sides by -1, we want the x² term to be positive)
(x - 4)(x + 1) = 0 (factor)
so
x - 4 = 0, then x = 4
and
x + 1 = 0, then x = -1
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
h(x)=4x^2-36x+81
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The numbers would be 1 and 6 you need to put the positive on the 6 and the negative on the 1 to get positive 5 when adding and -6 when multiplying
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