<span>Just solve this by using the molar mass/molecular weight, and the avogadros number in a dimensional analysis
18.46 g Cu x (1 mole/64 g) x (6.022 x 10^23 atoms/1 mole) = 1.74 x 10^23 atoms
</span><span>67.69 g NaCl x (1 mole/58 g) x (6.022 x 10^23 formula units/ 1 mole) = 7.03 x 10^23 formula units
</span>44.99 g H2O x (1 mole/18 g) x (6.022 x 10^23 molecules/ 1 mole) = 1.51 x 10^24 molecules
<span>0.250 moles Mg x (24 g/1 mole) = 6 g
</span>48.096 g S x (1 mole/32 g) = 1.5 g
Answer:
Keep it simple. If all the oxygen contained in the 200 grams of potassium chlorate is produced in the decomposition, then all we have to do is find out how many grams of oxygen are there in the 200 grams. This we can do by calculating the ratio of oxygen mass to the whole. Using 39.1 for potassium, 35.45 for chlorine and 3 times 16, or 48 for the oxygen, we get a total of 122.55 grams per mole for potassium chlorate, of which 48 grams are oxygen. This ratio is 48/122.55. This ratio times the original 200 grams of the compound, gives us 78.34 grams of oxygen produced.Explanation:
The answer to this would be 3,265,440
hope this helps
hey there!:
2HgO (s) => 2Hg (l) + O2 (g)
2 moles of HgO decompose to form 2 moles of Hg and 1 mole of O2 according to the reaction mentioned in the question.
So 4.00 moles of HgO must give 4 moles of Hg and 2 moles of O2 theoretically.
603 g of Hg = 603 / 200.6 = 3 moles
Percent yield = ( actual yield / theoretical yield) * 100
= ( 3/4) * 100
= 75 %
Hope this helps!
