Question

Please help me, It's my last question :)

Answer 1

Given:

$V_{1} = \text{5 L}$

$T_{1} = \text{298 K}$

$V_{2} = \text{3 L}$

Unknown:

$T_{2}$

Solution:

$\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}$

$T_{2} = T_{1} \times \dfrac{V_{2}}{V_{1}}$

$T_{2} = \text{298 K} \times \dfrac{\text{3 L}}{\text{5 L}}$

$\boxed{T_{2} = \text{179 K}}$

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