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3 years ago

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Which ordered pairs are solutions to the inequality x – 2y < 5? Choose all answers that are correct. Question 9 options: (0,

4) (–1, –3) (1, 3) (2, –3) (–3, –2) PSA I AM ON A TIMER SO PLEASE HELP!

1 answer:

kkurt [141]3 years ago

6 0

(0,4) , (1,3) , (-3,-2)

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For function one, the slope is already in mx+b form. The coefficient to x is the slope, so it is four in this case. For the second function we calculate the slope using rise over run. The rise is change in y and run is change in x, so 4/2= 2 slope. Four is greater than two so it has the greater rate of change. The answer is B

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2 years ago

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A train leaves the station at 9:00 pm traveling east at 36 miles per hour. A second train leaves the station at 10:00 pm traveli

sveta [45]

The answer is c.6:00 am

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3 years ago

How do you determine the net force of an object?

Dvinal [7]

Answer:

you determine net force of an object by using this formula:

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2 years ago

Jason consumes 1500 calories and needs to

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Answer:

100*150=15000 calories

Step-by-step explanation:

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2 years ago

Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)

Gnom [1K]

Answer: Horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

Step-by-step explanation:

Since we have given that

$y=\dfrac{x^2-9}{4x^2+1}$

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is $4x^2+1$

Now,

$4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}$

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

$y=\dfrac{1}{4}$

Hence, horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

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3 years ago