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kumpel [21]
3 years ago
15

Consider a population list x, with a CV= 10%. A second population list, y, has a CV= 20%. The linear regression of y on x is y =

10x. What is the correlation between y and x? (Assume linearity, homoscedasticity, no outliers and normality)
Mathematics
1 answer:
ch4aika [34]3 years ago
6 0

Answer:

The correlation coefficient 0.5 depicts that there is moderate positive correlation between y and x.

Step-by-step explanation:

The linear regression equation is

y= a+bx

The given linear equation is

y= 10x

Here, slope=b=10 and intercept=a=0.

From above equation,

ybar=10xbar

We are given that CVx=0.1 and CVy=0.2

where CV=(standard deviation/mean)*100

We know that

b=r(Sy/Sx)

Multiplying by xbar/ybar on both sides

(xbar/ybar)b=r(Sy/Sx)(xbar/ybar)

(xbar/ybar)b=r[(Sy/ybar)/(Sx/xbar))]

(xbar/ybar)b=r[CVy/CVx]

As CVy/CVx=(Sy/ybar)*100/(Sx/xbar)*100=(Sy/ybar)/(Sx/xbar).

By putting ybar=10xbar, b=10, CVx=0.1 and CVy=0.2.

(xbar/10xbar)10=r(0.2/0.1)

1=r(0.2/0.1)

1=r(2)

r=0.5

There is moderate positive correlation between y and x.

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Answer:

Step-by-step explanation:

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order from the largest :

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Answer:

Domain: 5, 6, 7, 8

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The relation is a function because each x-value has its own y-value.

Step-by-step explanation:

Domain: Set of all first elements in relation

Range: Set of all second elements in relation

How to determine if the relations is a function:

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2. Identify the output values.

3. If each input value leads to only one output value, classify the relationship as a function.

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An exponential function f(x) is reflected across the y-axis to create function g(x). Which is a true statement regarding f(x) an
Natalija [7]

We are given

An exponential function f(x) is reflected across the y-axis to create function g(x)

we know that whenever we have to reflect any function about y-axis , we will always replace x as -x

so, we reflect f(x) about y-axis

so, we can replace x as -x

we get new function as

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and that is g(x)

so, we get

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Initial value means value of function at x=0

so, we will plug x=0

we get

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we can see that both f(x) and g(x) have same initial value

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However, we also know that the function y-values do not change. This is because whatever the x values are don't change the range and y-values of an even function.

To be more specific, if we have an even function, we are most likely dealing with quadratics or variants/transformations of the quadratic function.

If we were to have 2, and -2, and we wanted to plug them into the equation:
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