X + 5y = 1 . . . . (1)
8x - 2y = 3 . . . .(2)
Solution 1.
From (1), x = 1 - 5y
substituting for x in (2), we have:
8(1 - 5y) - 2y = 3
8 - 40y - 2y = 3
8 - 42y = 3
42y = 5
y = 5/42
x = 1 - 5(5/42) = 1 - 25/42 = 17/42.
Solution 2.
Multiply (1) by 8, to get:
8x + 40y = 8 . . . . . (3)
(3) - (2) = 40y - (-2y) = 8 - 3
42y = 5
y = 5/42
substitute for y into (3), to get:
8x + 40(5/42) = 8
8x + 100/21 = 8
8x = 8 - 100/21 = 68/21
x = (68/21)/8 = 17/42
Answer:
Consider the parent logarithm function f(x) = log(x)
Now,
Let us make transformations in the function f(x) to get the function g(x)
•On streching the graph of f(x) = log(x) , vertically by a factor of 3, the graph of y = 3log(x) is obtained.
•Now, shrinking the graph of y = 3log(x) horizontally by a fctor of 2 to get the grpah of y = 3log(x/2) i.e the graph of g(x)
Hence, the function g(x) after the parent function f(x) = log(x) undergoes a vertical stretch by a factor of 3, and a horizontal shrink by a factor of 2 is
g(x) = 3 log(x/2) (Option-B).
Answer:
r = 2.23
Step-by-step explanation:
Use the formula:
C = 2(pi)r
Solve for r:
r = C
/2π = 14
/2·π = 2.228
Answer:
x = 1 , 7
Step-by-step explanation:
Solution:-
- The given equation is as follows:
y = x^2 - 8x + 7
- We can solve the above equation by either making factors or by using Quadratic formula.
Factor Approach:
- Using the constant "7" at the end of the quadratic equation we will determine two integer multiples such that their additions/subtraction results in "-8".
- So the only factor of "7" are:
7 x 1 = 7
-7 x -1 = 7
- We see that addition/subtraction of first (7 , 1 ) does not results in "-8", However, the sum of ( -1 , -7 ) = -1 - 7 = -8. So the correct factors are ( -1 , -7 ). So we replace "-8x" with our factors "-1x" and "-7x":
x^2 -x -7x + 7 = 0
- Take common multiples out of pair of two terms:
x*(x-1) -7*(x-1) = 0
(x-7)*(x-1) = 0
- So we equate each term in bracket with "0" and evaluate the values of x:
(x-7) = 0 , x = 7
(x-1) = 0 , x = 1
- So the solution to the quadratic equation is:
x = 1 , 7
Answer: 
Step-by-step explanation:
In order to solve this exercise it is important to remember the multiplication of signs. Notice that:
In this case you have the following expression given in the exercise:
Where the variable is "j".
When you multiply signs, you get:
Now you need to identify that like terms and then you need to add them (or combine them). So, applying this procedure you get that the simplified form of the expression is the shown below:
As you can observe, you get a 2nd degree binomial.
