Answer:
The time the two planes will meet is 1.43 hours
Step-by-step explanation:
Given;
speed of the first plane in positive direction, = 40 mph
speed of the second plane in negative direction(opposite direction) = -100 mph
distance between the two planes = 200 miles
Let the time the two planes will meet = t
the position of the first plane at this time "t" = 40t
the position of the second plane at this time "t" = -100t
(40t)>--------------------------------<(-100t), this space between them is 200 miles.
Thus, the difference in the distance they traveled before meeting should be equal to 200 miles.
40t - (-100t) = 200
40t + 100t = 200
140t = 200
t = 200 / 140
t = 1.43 hours
Therefore, the time the two planes will meet is 1.43 hours
Yes that is right
x=-4 is a vertical line passing through the points (-4,y)
where y can be any value
Answer:
s(n) = 20
s = 20/n
Step-by-step explanation:
Answer:
the answer is additive inverse
Answer:
P(F/E) = 0.5
Step-by-step explanation:
We have the following information:
P(E∩F)=0.1
P(E)=0.2
Additionally, the probability P(A/B) of event A given Event B is calculated as:
P(A/B) = P(A∩B)/P(B)
Now, we want the probability P(F/E), so it is calculated as:
P(F/E) = P(E∩F)/P(E)
Finally, replacing the values we get:
P(F/E) = 0.1 / 0.2
P(F/E) = 0.5
