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Gnoma [55]
3 years ago
15

A miner develops cancer of the esophagus. Ten years before, he had been exposed to radiation when he worked for a year in a mine

. He had also smoked cigarettes for a number of years, but had quit five years ago. Which statement best describes the miner’s condition?
A. Tests can determine whether the cancer was caused by exposure at the mine or by compounds in cigarette smoke so that a treatment can be determined.

B. Cancer caused by exposure at the mine would have appeared while he was at the mine, so smoking is the more likely cause.

C. The cancer is likely the result of natural exposure to radiation in the environment and not related to either the mine or smoking.

D. It is unlikely that a specific cause can be determined, but the treatment would likely be the same in either case.
Chemistry
2 answers:
sashaice [31]3 years ago
4 0

D) It is unlikely that a specific cause can be determined, but the treatment would likely be the same in either case

Salsk061 [2.6K]3 years ago
3 0

Answer:

Option (D).

Explanation:

Cancer can be defined as a progressive disease, which involves uncontrolled cell growth with ability to spread or invade other parts organs of the body. It is resulted due to a number of mutations that lead to change in genetic material and cause destruction of cell cycle regulation.

As the miner had been exposed with both radiation and tobacco, it is quite tough to determined a specific cause for his cancer. This may be due to radiation or smoke or due to other factors.

Although treatment for cancer caused by either way would be same as it will target the cancer cells and kill them by prevent their growth and division.

Thus, the correct answer is option (D).  

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To solve this question we must find the molar mass of methane in order to find the moles of methane added. With the moles of methane and the chemical equation we can find the moles of water produced and its mass:

<em>Molar mass CH₄:</em>

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2g/mol + 16g/mol = 18g/mol

<em>Mass water:</em>

3.0moles H₂O * (18g / mol) =

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