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Naddik [55]
3 years ago
7

From his experiments, J. J. Thomson concluded that

Chemistry
2 answers:
In-s [12.5K]3 years ago
7 0
<span>atoms contain small negatively charged particles that are called electrons.</span>
sergiy2304 [10]3 years ago
6 0
Answer: option D. Atoms containd small negatively charged particles that are called electrons.

JJ Thompson carried out three important experiments with cathode rays. With them he proveed that cathode rays were negative charged particles and that the ratio charge/mass was so large that the particles either had a huge charge or had a very small mass, and he came up with the latter, defining that these negative charged particle were very small.
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IF 500 mL of air contains 2.50x10^22 particles (atoms and molecules). how much particles do you inhale in one day if you breath
vaieri [72.5K]

Answer:

I think it is 0.00192

Explanation:

28.795705

15000

=0.00192

8 0
3 years ago
What is the percent composition of NaHCO3?
zhuklara [117]

Answer:

                Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)

Explanation:

<em>Percent Composition</em> is defined as the <u><em>%age by mass of each element present in a compound</em></u>. Therefore, it is a relative amount of each element present in a compound.

Calculating Percent Composition of NaHCO₃:

1: Calculating Molar Masses of all elements present in NaHCO₃:

              a) Na  =  22.99 g/mol

             b) H  =  1.01 g/mol

              c) C  =  12.01 g/mol

              d) O₃  =  16.0 × 3 =  48 g/mol

2: Calculating Molecular Mass of NaHCO₃:

              Na  =  22.99 g/mol

             H    =  1.01 g/mol

              C    =  12.01 g/mol

              O₃  =  48 g/mol

                       ----------------------------------  

Total                  84.01 g/mol

3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:

For Na:

                 =  22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  27.36 %

For H:

                 =  1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  1.20 %

For C:

                 =  12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  14.29 % ≈ 14.30 %

For O:

                 =  48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  57.13 % ≈ 57.14 %

8 0
3 years ago
2) 183 cg =<br> kg<br> 5<br> .00183 kg<br> 0.0183 kg<br> .183 kg<br> 3) 0.25 kg =<br> g
OlgaM077 [116]

Answer:

183 cg = 0.00183 kg

0.25 kg = 250 g

Explanation:

Use conversion factors. 1kg is equal to 1 x 10^5 cg (100000) and 1 kg is equal to 1 x 10^3 grams (1000 grams).

5 0
4 years ago
Help please fast as possible I’ll mark you brainlist
Sergeeva-Olga [200]

Answer:

As mass increases the gravitational force increases

Explanation:

Things with mass gain a gravitational force, The bigger they are the more force, for example: the sun is the biggest so it pull us

7 0
3 years ago
A balance is used to measure mass
FrozenT [24]

if this is true or false its true hope i helped

6 0
3 years ago
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