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UNO [17]
3 years ago
6

An ore sample with a mass of 92.3 g is found to contain 17.7% by mass iron. What mass of iron is contained in the ore?

Chemistry
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

19.18g of iron

Explanation:

To find the mass of iron, we simply find the amount of the ore in grammes that corresponds to 17.7% iron.

We can do this mathematically. We simply place the 17.7 over 100 and multiply by the total mass of the iron.

The mass of iron in the ore is thus: 17.7/100 * 92.3 = 19.18g

The ore simply contains a mass of 19.18g of iron

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How many moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 ATM
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Answer:

285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

  • P= 200.8 atm
  • V= 35 L
  • n=?
  • R= 0.082 \frac{atm*L}{mol* K}
  • T= 27.3 C= 300.3 K (being O C= 273 K)

Replacing:

200.8 atm* 35 L= n* 0.082\frac{atm*L}{mol* K} * 300.3 K

Solving:

n=\frac{200.8 atm* 35 L}{0.082\frac{atm*L}{mol* K} * 300.3 K}

n= 285.4 moles

<u><em>285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.</em></u>

<u><em></em></u>

5 0
3 years ago
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