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UNO [17]
3 years ago
6

An ore sample with a mass of 92.3 g is found to contain 17.7% by mass iron. What mass of iron is contained in the ore?

Chemistry
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

19.18g of iron

Explanation:

To find the mass of iron, we simply find the amount of the ore in grammes that corresponds to 17.7% iron.

We can do this mathematically. We simply place the 17.7 over 100 and multiply by the total mass of the iron.

The mass of iron in the ore is thus: 17.7/100 * 92.3 = 19.18g

The ore simply contains a mass of 19.18g of iron

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7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.
Effectus [21]
<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

  • 5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

  • The units used to measure length include;

Kilometer(km)

10

Hectometer (Hm)

10

Decameter (dkm)

10

Meter(m)

10

Decimeter (dm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

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3 years ago
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Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)
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Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
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G Mn = 0
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Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
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