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morpeh [17]
3 years ago
7

Air is compressed in a piston–cylinder device from 90 kPa and 20°C to 650 kPa in a reversible isothermal process. Determine the

entropy change of air. The gas constant of air is R = 0.287 kJ/kg·K. (You must provide an answer before moving on to the next part.)
Chemistry
1 answer:
Sophie [7]3 years ago
4 0

Answer:

-0.5674 \frac{kJ}{kgK}

Explanation:

The entropy change of an ideal gas can be calculated by:

s_{2}-s_{1}=Cpln(\frac{T_{2}}{T_{1}})-Rln(\frac{P_{2}}{P_{1}})

You can review its deduction on van Wylen 6 Edition, section 8.10.

This is an isothermal process, so the entropy change will be calculated as:

s_{2}-s_{1}=-Rln(\frac{P_{2}}{P_{1}})

s_{2}-s_{1}=-0.287*ln(\frac{650}{90})=-0.5674[tex]\frac{kJ}{kgK}[/tex]

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When an oxygen atom is attached to a carbon atom, the carbon atom becomes reduced.
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3 years ago
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If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?
Ipatiy [6.2K]

It takes 21.3 days

<h3>Further explanation</h3>

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

\tt \dfrac{5000~g}{46~g/mol}=108.7~moles

moles of glucose to produce 108.7 moles ethanol :

\tt \dfrac{1}{2}\times 108.7=54.35

54.35 moles = 5 hours

moles of 1000 kg of glucose :

\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles

So for 5555.5 moles, it takes :

\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days

7 0
3 years ago
Which equation will you use to calculate the volume of a 5.00 liter sample of air at 50°C when it is warmed to 100°C at constant
Alexandra [31]
I believe it's a proportion of volume over temperature = volume and temperature. cross multiply and divide and see what u get. if it looks right go fro it if not try something else. I hope this helps!
6 0
3 years ago
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What is the mass of 15 moles of carbon atoms? Round your answer to the nearest hundredth
Georgia [21]

In order to convert the moles of a substance to grams, you will need to multiply the mole value of the substance by its molar mass. More commonly written for this application as: where, is the molar mass of the substance.

Hope this helped

:)

4 0
3 years ago
How many moles of nitrogen are in 3.7 moles of C8H11NO2?
Phoenix [80]
<h3>Answer:</h3>

               3.7 Moles of Nitrogen

<h3>Explanation:</h3>

                      On observing the chemical formula C₈H₁₁NO₂ (might be formula of Dopamine) it is found that one mole of this compound contains;

8 Moles of Carbon

11 Moles of hydrogen

1 Mole of Nitrogen and

2 Moles of Oxygen respectively.

<u>Calculate Number of Moles of Nitrogen:</u>

As,

                   1 Mole of C₈H₁₁NO₂ contains  =  1 Mole of Nitrogen

So,

            3.7 Moles of C₈H₁₁NO₂ will contain  =  X Moles of Nitrogen

Solving for X,

                       X  =  (3.7 Moles × 1 Mole) ÷ 1 Mole

                       X  =  3.7 Moles of Nitrogen

4 0
3 years ago
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