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3 years ago

State the domain of d.

Mathematics

2 answers:

Mila [183]3 years ago

5 0

domain is for variable x

ans is

tester [92]3 years ago

4 0

d(x) = { (x,y): y = sqrt(x) and y >=0 }

since sqrt function requires x to be >=0 so

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What is the value y ?

Morgarella [4.7K]

Answer: y=3 x=4

Step-by-step explanation:

Its a rectangle so the 2 horizontal sides are even and the vertical sides are even. So, since one side is 10, the other side has to be 10. So, 2y+4 = 10. subtract 4 from each side getting 2y = 6. divide by 2 to get the y by its self and you get y = 3.

For the horizontal side, 10 + 2x = 18. subtract 10 from each side. 2x = 8 divide by 2. x = 4

7 0

3 years ago

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

Read more about expressions at:

brainly.com/question/723406

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5 0

2 years ago

Please help answer correctly !!!!!!!!! Will mark Brianliest !!!!!!!!! URGENT

krek1111 [17]

Answer:

5 00000

Step-by-step explanation:

bc it just is lolllllll

7 0

3 years ago

What is the solution of the equation (x – 5)2 3(x – 5) 9 = 0? use u substitution and the quadratic formula to solve.

Ahat [919]

The value of x in the equation $(x-5)^{2} +3(x-5)+9=0$ is x=(7+3 $\sqrt{3}i$ )/2,

(7-3 $\sqrt{3}i$ )/2.

Given equation $(x-5)^{2} +3(x-5)+9=0$ .

We have to find the solution of the equation.

Equation is solved to find the value of variables. The number of values of the variable depends on the highest power of variables.

let (x-5)=u-------------------1

equation becomes $u^{2} +3u+9=0$

solution of a quadratic formula

x=-b± $\sqrt{b^{2} -4ac}$ /2a

on comparing with general form a=1,b=3, c=9

u=-3± $\sqrt{3^{2} -4*1*9} /2$

=-3± $\sqrt{9-36}/2$

=-3± $3\sqrt{-27}/2$

=-3± $3\sqrt{3} i/2$

$u_{1} =-3$ +3 $\sqrt{3}/2$ , $u_{2}$ =-3-3 $\sqrt{3}/2$

put the values of $u_{1}$ in equation 1

x-5= $u_{1}$

x-5=-3+ $3\sqrt{3} /2$

x=-3+3 $\sqrt{3}i/2+5$

x=7+3 $\sqrt{3} i/2$

put the values of $u_{2}$ in equation2

x-5= $u_{2}$

x-5=-3-3 $\sqrt{3} /2$

x=7-3 $\sqrt{3}/2$

Hence the values of x are 7+3 $\sqrt{3}i/2$ , 7-3 $\sqrt{3}i/2$ .

Learn more about equation at brainly.com/question/2972832

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5 0

2 years ago

What is the percent increase?Original quantity:50 new quantity 56

Semmy [17]

Answer:

This is a 12% change

Step-by-step explanation:

To find the percent change, use the percent change equation.

(New - Old)/(Old) * 100 = Percent Change

(56 - 50)/(50)*100 = Percent Change

6/50 * 100 = Percent Change

.12 * 100 = Percent Change

12% = Percent Change

5 0

3 years ago