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HACTEHA [7]
3 years ago
5

g A restaurant offers 7 entrees and 11 desserts. In how many ways can a person order a two-course meal?

Mathematics
1 answer:
Kitty [74]3 years ago
8 0

Answer:

2-course\ meal = 77\ ways

Step-by-step explanation:

Given

Entrees = 7

Desserts = 11

Required

Determine the number of ways to get a two-course meal

This is solved as follows:

<em>The entrees can be ordered in 7 ways</em>

<em>The desserts can be ordered in 11 ways;</em>

2-course\ meal = Entrees * Desserts

Hence:

2-course\ meal = 7 * 11

2-course\ meal = 77\ ways

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The sum of the 3 angles in a triangle = 180°, that is

∠ 1 + ∠ 2 + ∠ 3 = 180°

Given ∠ 1 + ∠ 2 = 134°, then

134° + ∠ 3 = 180° ( subtract 134° from 180° )

∠ 3 = 46° → D

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hammer [34]

Answer:

208

Step-by-step explanation:

6×4=24

24×2=48

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2 years ago
10) Show that in a group of 10 people (where any two people are either friends or enemies), there are either three mutual friend
ddd [48]

Answer with explanation:

Number of People in the group =10 People

The combination between two people is that, they can be either friends or enemies.

Total number of Possible Relation

                            =18 +16+14+12+10+8+6+4+2

                            = 90 Relations in all.

Out of 90 relations , 45 will be friends and 45 will be enemies.

⇒Now, we have to prove that, between 10 people, there are either three mutual friends or four mutual enemies, and there are either three mutual enemies or four mutual friends.

→→If there are three mutual friends, total number of people in the group =3 ×2=6 people in the group

And, four mutual enemies in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual friends or four mutual enemies

   =6 +4

   =10

Hence proved.

→→→→Second part is ,in this group there can be either three mutual enemies or four mutual friends.

⇒If there are three mutual enemies, total number of people in the group =3 ×2=6 people in the group

And, four mutual friends in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual enemies or four mutual enemies

   =6 +4

   =10

Hence proved.

3 0
3 years ago
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