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HACTEHA [7]
3 years ago
5

g A restaurant offers 7 entrees and 11 desserts. In how many ways can a person order a two-course meal?

Mathematics
1 answer:
Kitty [74]3 years ago
8 0

Answer:

2-course\ meal = 77\ ways

Step-by-step explanation:

Given

Entrees = 7

Desserts = 11

Required

Determine the number of ways to get a two-course meal

This is solved as follows:

<em>The entrees can be ordered in 7 ways</em>

<em>The desserts can be ordered in 11 ways;</em>

2-course\ meal = Entrees * Desserts

Hence:

2-course\ meal = 7 * 11

2-course\ meal = 77\ ways

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An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
3 years ago
If someone makes $650 a week, how much will they make in a<br> year?
Arlecino [84]

Answer:

they will make $33,800 in a year.

Step-by-step explanation:

there are 52 weeks in a year, so $650×5= $33,800

5 0
2 years ago
Olya would like to find a way to reduce her current debt. The table below shows Olya’s monthly income, expenses and net income A
Viktor [21]
<span>b.<span>Olya could skip a month or two paying for her school loan and put the money towards her credit card debt.</span></span>
8 0
3 years ago
Read 2 more answers
The denominator of a fraction is 10 more than its numerator.
Dennis_Churaev [7]

The right answer is Option C : 5

Step-by-step explanation:

Let,

The numerator of fraction = x

The denominator of a fraction is 10 more than its numerator.

\frac{x}{x+10}

When 1/3 is added to this fraction,

\frac{x}{x+10}+\frac{1}{3}

the resulting fraction’s denominator is three times the denominator of the original fraction its numerator is 15 less than its denominator

\frac{3(x+10)-15}{3(x+10)}

Therefore, it becomes

\frac{x}{x+10}+\frac{1}{3} = \frac{3(x+10)-15}{3(x+10)}

Taking LCM on left side

\frac{3x+(x+10)}{3(x+10)}=\frac{(3x+30)-15}{3(x+10)}\\\\\frac{3x+x+10}{3(x+10)}=\frac{3x+30-15}{x(x+10)}\\\\\frac{4x+10}{3(x+10)}=\frac{3x+15}{3(x+10)}

Multiplying both sides by 3(x+10)

3(x+10)*\frac{4x+10}{3(x+10)}=\frac{3x+15}{3(x+10)}*3(x+10)\\4x+10=3x+15\\4x-3x=15-10\\x=5

The numerator of original fraction is 5.

The right answer is Option C : 5

Keywords: fraction, addition

Learn more about fractions at:

  • brainly.com/question/11207748
  • brainly.com/question/11280112

#LearnwithBrainly

8 0
3 years ago
Help Which is the product of 15 and 5/12
77julia77 [94]

Answer:

the answer to your question would be b,6 1/4

6 0
3 years ago
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