The answer to this question is E.
Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
Answer:

Step-by-step explanation:
Given that the 45% of the population of a city are men and 15% are children . The number of women is 64,400 . And we need to find the number of children . Here ,
So the percentage of women will be equal to [ 100 - ( 45 -15) ]% = [ 100 - 60 ]% = 40% .
So let us take the total number of people be x . So ,


<u>The </u><u>percentage</u><u> of</u><u> </u><u>children </u><u>=</u><u> </u><u>1</u><u>5</u><u>%</u><u> </u><u>:</u><u>-</u>

Here you go! Sorry I took forever to answer!
Y=12x-10
Explanation:
You basically what to get y by itself so-
12x-y=10
You will add y to both sides
12x=y+10
Then subtract ten from both sides
12x-10=y or y=12x-10