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coldgirl [10]
2 years ago
6

Simplify the trigonometric expression.

Mathematics
1 answer:
marusya05 [52]2 years ago
4 0

Answer:

from the working in the photo

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What is the equation of the line????????
IrinaVladis [17]

Answer:

y=1/2x+2

Step-by-step explanation:

The equations come in the form of y=mx+c, where m is the gradient and c is the y-intercept. Looking at the graph we know that the y-intercept is (0,2), so that rules out options B and C.

To find the gradient is a little more tricky, but we can follow the formula:

\frac{rise}{run}, where rise is the vertical value and run is the horizontal value

So we sub in our values:

\frac{2}{4}

And simplify:

\frac{1}{2}

So now we sub in our new found values into y=mx+c:

y=1/2x+2

8 0
2 years ago
Read 2 more answers
Please help! This assignment is due soon! (In The photo)
eimsori [14]

Answer

Elena must have substracted 1/2x from both sides of the equation.

Lin must have multiplied both sides of the equation by 2

Explanation

The equation given is

\frac{1}{2}x+3=\frac{7}{2}x+5

For Elena to have arrived at

3=\frac{7}{2}x-\frac{1}{2}x+5

Then Elena must have substracted 1/2x from both sides of the equation.

That is;

\begin{gathered} \frac{1}{2}x+3=\frac{7}{2}x+5 \\ \text{Substracting }\frac{1}{2}x\text{ from both sides of the equation will give Elena first step} \\ \frac{1}{2}x+3-\frac{1}{2}x=\frac{7}{2}x+5-\frac{1}{2}x \\ 3=\frac{7}{2}x-\frac{1}{2}x+5 \end{gathered}

For Lin to have arrived at

x+6=7x+10

It shows Lin must have multiplied both sides of the equation by 2

That is;

\begin{gathered} \frac{1}{2}x+3=\frac{7}{2}x+5 \\ \text{Multiply both sides of the equation by the lowest common mutiple } \\ \text{of the denominator which is 2.} \\ \frac{1}{2}x(2)+3(2)=\frac{7}{2}x(2)+5(2) \\ x+6=7x+10 \end{gathered}

4 0
1 year ago
Subtract. 5x^2-5x+1-(2x^2+9x-6)
Talja [164]
<h2>Hello!</h2>

The answer is:

3x^{2} -14x+7

<h2>Why?</h2>

To solve the problem we need to add/subtract like terms. We need to remember that like terms are the terms that share the same variable and the same exponent.

For example, we have:

x^{2} +2x+3x=x^{2} +(2x+3x)=x^{2}+5x

We have that we were able to add just the terms that were sharing the same variable and exponenr (x for this case).

So, we are given the expression:

5x^2-5x+1-(2x^2+9x-6)=5x^{2}-2x^{2}-5x-9x+1-(-6)\\\\(5x^{2}-2x^{2})+(-5x-9x)+(1-(-6))=3x^{2}-14x+7

Hence, the answer is:

3x^{2} -14x+7

Have a nice day!

4 0
3 years ago
store owner decides to mark up all items by 30%. What is the selling price of an item that originally cost $10?
Artist 52 [7]
0.030 × 10 =.0.3. 0.3 +10 = 10.3
6 0
3 years ago
The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th
ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}

By doing so, we find:

|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1

4 0
2 years ago
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