3 years ago

Which of the following is a geometric sequence?

Mathematics

2 answers:

KIM [24]3 years ago

8 0

Answer:

Step-by-step explanation:

The answer is D with the common ratio 4.

Savatey [412]3 years ago

6 0

You need to find which one is in order

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Emily bought 4 cheeseburgers for $6 each and then spent $18 on a new shirt. She paid for the cheeseburgers and shirt with her de

Soloha48 [4]

-42 would be the answer

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3 years ago

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−3 |x| +2x−1 if x=−5

Varvara68 [4.7K]

−3 |-5| +2(-5)−1

-15 +2(-5)-1

-15-10-1

-26

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3 years ago

the flower shop had 40 times as many flowers in one cooler as Julia has in her bouquet the cooler has 120 flowers how many flowe

Softa [21]

Answer:

3 flowers are in Julias bouquet

Step-by-step explanation:

120 divided by 40 = 3

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3 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

Please help me , i just need to past this !

OLga [1]

Answer:

Step-by-step explanation:

i would say c

3 0

3 years ago

Read 2 more answers