Tan x /(1 +sec x) + (1+sec x) /tan x
Tan x=sin x / cos x
1+ sec x=1 +1/cos x=(cos x+1)/cos x
Therefore:
tan x /(1 +sec x) =(sin x/cos x)/(cos x+1)/cos x=
=(sin x * cos x) / [cos x* (cos x+1)]=sin x /(Cos x+1)
(1+sec x) /tan x=[(cos x+1)/cos x] / (sin x/cos x)=
=[cos x(cos x+1)]/(sin x *cos x)=(cos x+1)/sin x
tan x /(1 +sec x) + (1+sec x) /tan x=
=sin x /(Cos x+1) + (cos x+1)/sin x=
=(sin²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
Remember: sin²x+cos²x=1⇒ sin²x=1-cos²x
=(1-cos²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
=2 cos x+2 / [sin x(cos x+1)]=
=2(cos x+1) / [sin x(cos x+1)]=
=2 /sin x
Answer : tan x /(1 +sec x) + (1+sec x) /tan x= 2/sin x
You need to find out how many problems Carl can do in a minute (unit rate), which is 20/55 or .36363636363. If you multiply it by 75 mins, you get 27.27, so the answer would be 27.
There really isn't any distributing done, as the perimeter is the total length of the shape, and since this is a rectangle it has two two equal sides, 7+7=14 and 13+13=26, 14+26=40 inches
The option which best describes the meaning of the term theorem is <span><u>B. A conclusion proved by deductive reasoning.
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This one bc there’s one point vertically and there’s no more than one point when you draw a vertical line down