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inysia [295]
3 years ago
7

What’s the domain and range of these two graphs?

Mathematics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

The domains of the first graph is (1.5, 0) and (4.5,0)

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The width of a rectangle is 2 units less than the length. The area of the rectangle is 63 units. What is the length, in units, o
Oduvanchick [21]

Answer: Length = 9 units

Step-by-step explanation:

Let L represent the length of the rectangle.

The width of a rectangle is 2 units less than the length. It means that the width of the rectangle is (L - 2) units.

The formula for determining the area of a rectangle is expressed as

Area = length × width

The area of the rectangle is 63 units. It means that

L(L - 2) = 63

L² - 2L = 63

L² - 2L - 63 = 0

L² + 7L - 9L - 63 = 0

L(L + 7) - 9(L + 7) = 0

L - 9 = 0 or L + 7 = 0

L = 9 or L = - 7

Since the length cannot be negative, then

L = 9 units

Width = 9 - 2 = 7 units

5 0
3 years ago
During a fundraiser, John raised $50, Susan raised $72, and Kara raised $65. Who has the greatest magnitude of money raised?
TiliK225 [7]

Answer:

Susan has the most money which is $72

Step-by-step explanation:

because john has $50 which is lower than $72 and kara has $65 which is lower than $72 so therefore susan has more money

5 0
3 years ago
Read 2 more answers
The graph of the piecewise function f(x) is shown.
iris [78.8K]
1. The range of a function is the set of all values that f can produce for all the x-es in the domain.

2. If we are given the graph, in order to find the range, we project the graph into the y axis. Informally, we draw the "shadow" of the graph into the y axis as in the FIGURE atached.

3. The range is <span>D || {y | −5 ≤ y ≤ −1}</span>

6 0
3 years ago
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given two squares, one with side length of 5 and the other with a side length of 7, what is the ratio of their areas?
Kaylis [27]

Answer:

25: 49

Step-by-step explanation:

5*5:7*7\\25: 49

7 0
3 years ago
V-16=-32<br>I need help with the math worksheet how to solve the question
sergeinik [125]

You solve an equation like this by adding the opposite of the constant to both sides of the equation.

... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b

... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0

... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V

_____

<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.

8 0
3 years ago
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