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steposvetlana [31]
3 years ago
8

Which equation has a graph parallel to the graph of 9x + 3y = -22 ?

Mathematics
2 answers:
trasher [3.6K]3 years ago
5 0
9x + 3y = -22     

3y = -9x - 22          

y = -3x - 22/3
slope m=-3
lines are parrallel when m1=m2

m1=-3
<span> Y = -3x + 8
</span>m2=-3
s0 B is right option
rodikova [14]3 years ago
3 0
9x + 3y = -22        |subtract 9x from both sides

3y = -9x - 22          |divide both sides by 3

y = -3x - 22/3

The line parallel to the line y = -3x - 22/3 has that same a slope.

Therefore your answer is B) y = -3x + 8.
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Manolo says that the solution of the equation g squared equals 36 is g = 6 because 6*6 = 36. Is Manolos reasoning complete? Expl
Gre4nikov [31]

Answer: No. Manolo forgot to include that the opposite of squaring a number is square rooting. If you take the square root of 36, you get 6. When you square a number, you multiply it by itself, which is what Manolo did. He multiplied 6 by itself and got the answer of 36.

Step-by-step explanation: Hope this helps!

3 0
3 years ago
graph each equation for the interval -360 is less than or equal to x and 360 is greater than or equal to x: y=1/2cos(2x+60)
lianna [129]

Answer:

See graph

Step-by-step explanation:

We want to graph y=\frac{1}{2}\cos(2x+60\degree) on the interval -360\degree \le x \le 360\degree

We need to plot some few points

(-30\degree,\frac{1}{2})

(-15\degree,\frac{\sqrt{3}}{4})

(0\degree,\frac{1}{4})

(15\degree,0)

(30\degree,-\frac{1}{4})

(45\degree,-\frac{\sqrt{3}}{4})

(60\degree,-\frac{1}{2})

(75\degree,-\frac{\sqrt{3}}{4})

(90\degree,-\frac{1}{4})

(105\degree,0)

(120\degree,\frac{1}{4})

(135\degree,\frac{\sqrt{3}}{4})

(150\degree,\frac{1}{2})

This will give us one cycle.

We then use the pattern to complete the graph on the interval

-360\degree \le x \le 360\degree

6 0
3 years ago
Can Someone Explain this to me please?
madreJ [45]

Answer:

I can, but i would be able to give you a more in depth explanation via g0ogle hangouts.

Step-by-step explanation:

7 0
3 years ago
Please help me figure this out! Thank you so much :( i really need it! ❤️
Hoochie [10]

Answer:

  \textbf{A. }x=2i\text{ or }x=-2i\\\\\textbf{B. }(x+2i)(x-2i)

Step-by-step explanation:

The quadratic can be solved in a straightforward way:

  x^2+4=0\\\\x^2=-4\qquad\text{subtract 4}\\\\x=\pm\sqrt{-4}\qquad\text{take the square root}\\\\x=\pm2i\qquad\text{simplify}

This tells you that the solutions are ...

  2i or -2i

__

For each root of "a", (x -a) is a factor. Thus the factors of the equation are ...

  (x +2i)(x -2i)

8 0
3 years ago
What is the GCF of 44j^5k^4 and 121j^2k^6?
Leviafan [203]

44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\  121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4

7 0
3 years ago
Read 2 more answers
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